这是一个模拟乐彩的小游戏，主体已完成，但是我想给他加一个按‘x’键才会离开，任意键继续的循环，然后就不知道怎么办了，如代码中‘#注释‘’我已尝试了应该是调用错了，还可以怎么做?
# -*- coding: utf-8 -*-
"""
乐彩小游戏
"""
import random
def generate_num():
auto_num = []
while len(auto_num)<6:
x = random.randint(1, 40)
if x not in auto_num:
auto_num.append(x)
return auto_num
def lottoCheck(a):
b=generate_num()
b_sort=sorted(b)
print("开出顺序：{}".format(b))
print("大小顺序：{}".format(b_sort))
print("您选的号码：{}".format(sorted(a)))
ans = set(a) & set(b_sort)
if len(ans):
print("匹配：{}".format(ans))
else:
print("不匹配！！！")
if __name__ == "__main__":
while True:
try:
user_nuber = input("请从1~39个号码任选5个不同的号码，每个号码请以逗号（,）隔开:")
if user_nuber.count(",")<4:
print("号码不足，",end="")
raise ValueError
else:
n1=[]
for n in user_nuber.split(","):
n = int(n)
if n in n1:
print("重复输入，",end="")
raise ValueError
elif n not in range(1,40):
print("超出范围！数字必须是1~39，",end="")
raise ValueError
else:
n1.append(n)
lottoCheck(n1)
break
except ValueError:
print("请再输入一次!")
#a=input("按x键离开，任选5个不同的号码继续：")
#if a !="x":
#n1.append(n)
#lottoCheck(n1)
#else:
#print("再见！")
"""
乐彩小游戏
"""
import random
def generate_num():
auto_num = []
while len(auto_num) < 6:
x = random.randint(1, 40)
if x not in auto_num:
auto_num.append(x)
return auto_num
def lottoCheck(a):
b = generate_num()
b_sort = sorted(b)
print("开出顺序：{}".format(b))
print("大小顺序：{}".format(b_sort))
print("您选的号码：{}".format(sorted(a)))
ans = set(a) & set(b_sort)
if len(ans):
print("匹配：{}".format(ans))
else:
print("不匹配！！！")
if __name__ == "__main__":
while True:
try:
user_nuber = input("按x键离开，或从1~39个号码任选5个不同的号码，每个号码请以逗号（,）隔开:")
if user_nuber == 'x':
break
if user_nuber.count(",") < 4:
print("号码不足，", end="")
raise ValueError
else:
n1 = []
for n in user_nuber.split(","):
n = int(n)
if n in n1:
print("重复输入，", end="")
raise ValueError
elif n not in range(1, 40):
print("超出范围！数字必须是1~39，", end="")
raise ValueError
else:
n1.append(n)
lottoCheck(n1)
break
except ValueError:
print("请再输入一次!")
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