题目:
Suppose that a website contains two tables, the Customers table and the Orders table. Write a SQL query to find all customers who never order anything.
Table: Customers.
+----+-------+
| Id | Name |
+----+-------+
| 1 | Joe |
| 2 | Henry |
| 3 | Sam |
| 4 | Max |
+----+-------+
Table: Orders.
+----+------------+
| Id | CustomerId |
+----+------------+
| 1 | 3 |
| 2 | 1 |
+----+------------+
Using the above tables as example, return the following:
+-----------+
| Customers |
+-----------+
| Henry |
| Max |
+-----------+
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/customers-who-never-order
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问题:
请问为啥我使用下面的代码,我可以跑出一模一样的结果,但是提交时候判定我是错的?感谢
SELECT a.Name as Customers
FROM (SELECT Name FROM Customers) AS a
WHERE Name NOT IN (
SELECT c.Name
FROM Customers c INNER JOIN Orders o
ON c.Id = o.CustomerId)
要用exists语句最方便,我帮你写一个试试看
select name from Customers c where not exists (select CustomerId from Orders where CustomerId = c.id)
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