题目
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output 4→3→2→1→5→6.
Input Specification:
Each input file contains one test case. For each case, the first line contains the address of the first node, a positive N (≤105 ^5
5
) which is the total number of nodes, and a positive K (≤N) which is the length of the sublist to be reversed. The address of a node is a 5-digit nonnegative integer, and NULL is represented by -1.
Then N lines follow, each describes a node in the format:
Address Data Next
where Address is the position of the node, Data is an integer, and Next is the position of the next node.
Output Specification:
For each case, output the resulting ordered linked list. Each node occupies a line, and is printed in the same format as in the input.
Sample Input:
00100 6 4
00000 4 99999
00100 1 12309
68237 6 -1
33218 3 00000
99999 5 68237
12309 2 33218
Sample Output:
00000 4 33218
33218 3 12309
12309 2 00100
00100 1 99999
99999 5 68237
68237 6 -1
#include <stdio.h>
#include <string.h>
int main()
{
char str[10];
scanf("%s",str);
int n,m;
scanf("%d %d",&n,&m);
struct listnode{
char ch[10];
int a;
char c[10];
}node[n+5],temp;
int i,j;
for(i=0;i<n;i++){
scanf("%s %d %s",node[i].ch,&node[i].a,node[i].c);
}
for(j=0;j<n;j++){
if(strcmp(str,node[j].ch)==0)
{
temp=node[0];node[0]=node[j];node[j]=temp;
break;
}
}
for(j=0;j<n-1;j++){
for(i=j+1;i<n;i++)
if(strcmp(node[j].c,node[i].ch)==0){
temp=node[j+1];node[j+1]=node[i];node[i]=temp;
break;
}
}
for(i=m-1;i>1||i==1;i--)
printf("%s %d %s\n",node[i].ch,node[i].a,node[i-1].ch);
printf("%s %d %s\n",node[0].ch,node[0].a,node[m-1].c);
for(i=m;i<n;i++)
{
printf("%s %d %s\n",node[i].ch,node[i].a,node[i].c);
}
}
错误信息
https://ask.csdn.net/questions/7424206?spm=1005.2025.3001.5141
参考这个写法
也许对你有帮助:https://blog.csdn.net/it_xiangqiang/category_10768339.html