两道关于python的英文问题，希望能分别解答

q1

Given the list of employees defined in the cell below, write python code to:

1. Process employees to create a new list of dictionaries named new_emp_list
   • Only include employees with firstnames Christine or Steve in the new list.

1. Print the length of the new list

1. Print the contents of the new list

Notes:

• This problem must be solved in ONE LINE using filter() with a SINGLE lambda funtion

employees = [
    {
        "email": "christine5663.howard@gmail.com",
        "employee_id": 201,
        "firstname": "Christine",
        "lastname": "Howard",
        "title": "Mrs",
        "work_phone": "(03) 7465 4973"
    },
    {
        "email": "paula592.campbell@gmail.com",
        "employee_id": 202,
        "firstname": "Paula",
        "lastname": "Campbell",
        "title": "Mrs",
        "work_phone": "(02) 2128 4700"
    },
    {
        "email": "steve5806.bird@gmail.com",
        "employee_id": 203,
        "firstname": "Steve",
        "lastname": "Bird",
        "title": "Mr",
        "work_phone": "(03) 3199 8017"
    }
]

# Insert all dicts with supplier_id=542 or employee_id=700 to the new list
# Write your code below this line

q2

Given a list of numbers, defined as variable numbers in the cell below, write python code to perform the following:

1. Find the minimum of the numbers in the list.
   • Write the code as a function named list_min and call the function with the list of numbers as parameter. Do not use any built-in functions such as min() (if you use the min() function, you will get only half of the marks). Instead, write your own code from first principles e.g. using a for loop and an if statement to compare and update the minimum value found so far.

1. Print the result so that we can see the outcome.

Skeleton code has been provided in the cell below to facilitate your task.

# 1. Define the function
def list_min(lst):
    
    min = None
    
    # Hint 1: 
    # Use a loop to process all items in the list
    # For each item, check if the item is smaller than the value stored in min
    # If it is, then assign the value of the current item to variable min
    # If it's not, do nothing
    
    # Hint 2: 
    # Be careful when comparing the min variable (especially when it is None) to an item in the list
    # If you are not careful, your code will crash
    # Check how it's done in the Severance book
    
    # Write your code below this line
    
            
    # Return the smallest value found        
    return min

# 2. Call the function with the list defined next
numbers = [42, 34, 10, 401, 52100]

# Write your code to call the function below this line
 

第一个部分代码

employees = [
    {
        "email": "christine5663.howard@gmail.com",
        "employee_id": 201,
        "firstname": "Christine",
        "lastname": "Howard",
        "title": "Mrs",
        "work_phone": "(03) 7465 4973"
    },
    {
        "email": "paula592.campbell@gmail.com",
        "employee_id": 202,
        "firstname": "Paula",
        "lastname": "Campbell",
        "title": "Mrs",
        "work_phone": "(02) 2128 4700"
    },
    {
        "email": "steve5806.bird@gmail.com",
        "employee_id": 203,
        "firstname": "Steve",
        "lastname": "Bird",
        "title": "Mr",
        "work_phone": "(03) 3199 8017"
    }
]
#firstnames Christine or Steve in the new list
new_list = list(filter(lambda x: x["firstname"] in ['Christine','Steve'], employees))
print(len(new_list))
print(new_list)
for item in new_list:
    item.update({'supplier_id':542})
    item['employee_id']=700
print(new_list)

：

employees = [
    {
        "email": "christine5663.howard@gmail.com",
        "employee_id": 201,
        "firstname": "Christine",
        "lastname": "Howard",
        "title": "Mrs",
        "work_phone": "(03) 7465 4973"
    },
    {
        "email": "paula592.campbell@gmail.com",
        "employee_id": 202,
        "firstname": "Paula",
        "lastname": "Campbell",
        "title": "Mrs",
        "work_phone": "(02) 2128 4700"
    },
    {
        "email": "steve5806.bird@gmail.com",
        "employee_id": 203,
        "firstname": "Steve",
        "lastname": "Bird",
        "title": "Mr",
        "work_phone": "(03) 3199 8017"
    }
]

new_emp_list = list(filter(lambda x: x["firstname"] in {"Christine","Steve"}, employees))
print(len(new_emp_list))
print(new_emp_list)

2

def list_min(lst):
    min = None
    for n in lst:
        if min is None or min > n:
            min = n
    return min

numbers = [42, 34, 10, 401, 52100]
print(list_min(numbers))

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