如何用Python实现三次0-9的循环，请大神帮帮我

for i in range(20):
    while (i%10)<12:
        (i%10)<10
        i+=1
        while i<10:
            j=i
            i=i+1
            print(f'{j}')

我自己试着编写了一下，无法进行第二次循环，请大神帮帮我

for i in range(3):
    for j in range(10):
        print(j)

是这样吗？

p = [1,2,3,4,5,6]
q = [0,0,0,0,0,0]
for i in range(5):
    for j in range(6):
        q[j] = p[j]+1
        if q[j] >=10:
            q[j] = q[j] % 10
    print(q)
    p = q

输出结果：

[2, 3, 4, 5, 6, 7]
[3, 4, 5, 6, 7, 8]
[4, 5, 6, 7, 8, 9]
[5, 6, 7, 8, 9, 0]
[6, 7, 8, 9, 0, 1]

我用的是python3.9

for i in range(2,7):
    for j in range(6):
        n = (i+j)%10
        print(n,end=" ")
    print()