Python递归函数实现列表的二分查找代码出错该怎么改

# 使用递归函数实现列表的二分查找


def seek(n,list,l = 0,r = len(list) - 1):


    while l <= r:


        mid = (l+r)//2


        if list[mid] > n:


            return seek(n,list,l = 0,r = mid - 1)


        elif list[mid] < n:


            return seek(n,list,l = mid + 1,r = len(list) - 1 )


        else:


            break


    print(mid)


seek(47,[4,11,23,34,47,56,75,88,98,102,122,135],l = 0,r = len(list) - 1 )


# TypeError: object of type 'type' has no len()

请在此代码上修改，错误已附在最后注释里，最后要输出查找结果！

新手求大佬指点！感谢！

# 使用递归函数实现列表的二分查找
def seek(n, list, l, r):
    while l <= r:
        mid = (l + r) // 2
        if list[mid] > n:
            return seek(n, list, l, mid - 1)
        elif list[mid] < n:
            return seek(n, list, mid + 1, r)
        else:
            break
    print(mid)


list = [4, 11, 23, 34, 47, 56, 75, 88, 98, 102, 122, 135]
seek(47, list, 0, len(list) - 1)

函数里的实参名不要用list，换一个名字，和关键字冲突了。