python怎么把文件夹中图片按一定数量分到不同文件夹

比如文件夹1中有300个图片，按98张图片一个文件夹分到文件夹1，2，3。最后一个文件夹放剩下的。图片已经按1.jpg,2.jpg命名好了。

import os,shutil

def run(file1):
    dir,file = os.path.split(file1)
    for i in range(2,5):
        os.mkdir(os.path.join(dir,f"{file}{i}"))
    for root,dirs,files in os.walk(file1):
        for img_name in files:
            num = int(img_name.split(".")[0])
            if num > 98 and num <= 98*2:
                shutil.move(os.path.join(file1, img_name),f"{file1}2")
            elif num > 98*2 and num <= 98*3:
                shutil.move(os.path.join(file1, img_name),f"{file1}3")
            elif num > 98*3:
                shutil.move(os.path.join(file1, img_name), f"{file1}4")
                
run("这里放你的300图片文件路径")

已经经过测试了 : 

import os,shutil

folder1 = r""
folder2 = r""
folder3 = r""
folder4 = r""

for img_name in os.listdir(folder1):
     if int(img_name.split("."))>98 and int(img_name.split("."))<=98*2:
          shutil.move(os.path.join(folder1,img_name),os.path.join(folder2,img_name))
     if int(img_name.split("."))>98*2 and int(img_name.split("."))<=98*3:
          shutil.move(os.path.join(folder1,img_name),os.path.join(folder3,img_name))
     shutil.move(os.path.join(folder1,img_name),os.path.join(folder4,img_name))

感谢大佬

好像有点不对int() argument must be a string, a bytes-like object or a number, not 'list'

可以可以，大佬牛逼