Python group的的结果再计算

import pandas as pd
import  numpy as np

df = pd.DataFrame({'key1':list('aabba'),
                  'key2': ['one','two','one','two','one'],
                  'data1': ['1','3','5','7','9'],
                  'data2': ['2','4','6','8','10']})
print(df)
grouped1 = df['data1'].astype(float).groupby(df['key1']).mean()     #先将data1转换成浮点型，然后分组求均值
print(grouped1)

  key1 key2 data1 data2
0    a  one     1     2
1    a  two     3     4
2    b  one     5     6
3    b  two     7     8
4    a  one     9    10
key1
a    4.333333
b    6.000000
Name: data1, dtype: float64

Process finished with exit code 0

假设我要对均值再除以10

直接grouped1/10就可以了