最近做一接口,要通过JAVA类请求SERVLET ,DOPOST方法.
不知道怎么把我的参数传过去.在网上找了几个例子.
都不行.
方法一:
[code="java"]
package com.3sfg.setvlet;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.Map;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.URIException;
import org.apache.commons.httpclient.methods.GetMethod;
import org.apache.commons.httpclient.methods.PostMethod;
import org.apache.commons.httpclient.params.HttpMethodParams;
import org.apache.commons.httpclient.util.URIUtil;
import org.apache.commons.lang.StringUtils;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
/**
@author leizhimin 2009-6-19 16:36:18
*/
public final class HttpTookit {
private static Log log = LogFactory.getLog(HttpTookit.class);
/**
* 执行一个HTTP GET请求，返回请求响应的HTML
*
* @param url 请求的URL地址
* @param queryString 请求的查询参数,可以为null
* @param charset 字符集
* @param pretty 是否美化
* @return 返回请求响应的HTML
*/
public static String doGet(String url, String queryString, String charset, boolean pretty) {
StringBuffer response = new StringBuffer();
HttpClient client = new HttpClient();
HttpMethod method = new GetMethod(url);
try {
if (StringUtils.isNotBlank(queryString))
//对get请求参数做了http请求默认编码，好像没有任何问题，汉字编码后，就成为%式样的字符串
method.setQueryString(URIUtil.encodeQuery(queryString));
client.executeMethod(method);
if (method.getStatusCode() == HttpStatus.SC_OK) {
BufferedReader reader = new BufferedReader(new InputStreamReader(method.getResponseBodyAsStream(), charset));
String line;
while ((line = reader.readLine()) != null) {
if (pretty)
response.append(line).append(System.getProperty("line.separator"));
else
response.append(line);
}
reader.close();
}
} catch (URIException e) {
log.error("执行HTTP Get请求时，编码查询字符串“" + queryString + "”发生异常！", e);
} catch (IOException e) {
log.error("执行HTTP Get请求" + url + "时，发生异常！", e);
} finally {
method.releaseConnection();
}
return response.toString();
}
/**
* 执行一个HTTP POST请求，返回请求响应的HTML
*
* @param url 请求的URL地址
* @param params 请求的查询参数,可以为null
* @param charset 字符集
* @param pretty 是否美化
* @return 返回请求响应的HTML
*/
public static String doPost(String url, Map<String, String> params, String charset, boolean pretty) {
StringBuffer response = new StringBuffer();
HttpClient client = new HttpClient();
HttpMethod method = new PostMethod(url);
//设置Http Post数据
if (params != null) {
HttpMethodParams p = new HttpMethodParams();
for (Map.Entry<String, String> entry : params.entrySet()) {
p.setParameter(entry.getKey(), entry.getValue());
}
p.setParameter("abc", "efg");
method.setParams(p);
}
try {
client.executeMethod(method);
if (method.getStatusCode() == HttpStatus.SC_OK) {
BufferedReader reader = new BufferedReader(new InputStreamReader(method.getResponseBodyAsStream(), charset));
String line;
while ((line = reader.readLine()) != null) {
if (pretty)
response.append(line).append(System.getProperty("line.separator"));
else
response.append(line);
}
reader.close();
}
} catch (IOException e) {
log.error("执行HTTP Post请求" + url + "时，发生异常！", e);
} finally {
method.releaseConnection();
}
return response.toString();
}
public static void main(String[] args) {
Map<String, String> map = new HashMap<String, String>();
map.put("parax", "123456");
String y = doGet("http://127.0.0.1:8080/AIRP/servletTest", "xx=00", "GBK", true);
String z = doPost("http://127.0.0.1:8080/AIRP/servletTest?", map, "GBK", false);
System.out.println(y);
System.out.println(z);
}
}[/code]
POST 方法 ,我在servletJ里,取不知任何参数,请求帮助.
感谢.
方法二:
[code="java"]
private static String testPost(String MSG_ID,String MOBILE_NO,String CONTENT,
String SERVICE_ID,String PASS,String SP_CODE,String LINK_ID,
String FEE_TYPE,String FEE_CODE) throws IOException {
URL url = new URL("http://127.0.0.1:8080/AIRP/servletTest");
URLConnection connection = url.openConnection();
connection.setDoOutput(true);
OutputStreamWriter out = new OutputStreamWriter(connection.getOutputStream(), "utf-8");
out.write("MSG_ID="+MSG_ID+"&MOBILE_NO="+MOBILE_NO+"&ACTION_ID=3"
+"&SERVICE_ID=99&PASS=asdfasd"
+"&SP_CODE=10625777&LINK_ID="); //向页面传递数据。post的关键所在！
// remember to clean up
out.flush();
out.close();
String sCurrentLine;
String sTotalString;
sCurrentLine = "";
sTotalString = "";
InputStream l_urlStream;
l_urlStream = connection.getInputStream();
// 传说中的三层包装阿！
BufferedReader l_reader = new BufferedReader(new InputStreamReader(
l_urlStream));
while ((sCurrentLine = l_reader.readLine()) != null) {
sTotalString += sCurrentLine + "\r\n";
}
System.out.println(sTotalString);
return sTotalString;
}
[/code]
if (params != null) {
HttpMethodParams p = new HttpMethodParams();
for (Map.Entry entry : params.entrySet()) {
p.setParameter(entry.getKey(), entry.getValue());
}
p.setParameter("abc", "efg");
method.setParams(p);
}
这样不知道怎么取不到参数...
因为没有做过这方面的需求，刚刚也搜索一下，发现有一篇文章涉及到了，LZ可以看看
http://winhonourxzg.iteye.com/blog/461219
因为dopost可以通过doget来进行调用，所以你直接在http://127.0.0.1:8080/AIRP/servletTest？加上需要传的参数是不是也可以出传递？
MS 方法二就是这样来做的。 :roll:
[size=xx-large][code="java"]if (params != null) {
HttpMethodParams p = new HttpMethodParams();
for (Map.Entry entry : params.entrySet()) {
p.setParameter(entry.getKey(), entry.getValue());
}
p.setParameter("abc", "efg");
method.setParams(p);
} [/code][/size]
改成了[size=xx-large]
int index = 0;
if(params != null){
data = new NameValuePair[params.size()];
for(Map.Entry entry : params.entrySet()){
data[index++] = new NameValuePair(entry.getKey(),entry.getValue());
}
}
method.setRequestBody(data);[/size]