SELECT a.org_id, a.org_name
FROM org a
WHERE a.org_parentid = 1
AND ((a.org_id in
(select org_id
from user_org
where user_id in (select user_.user_id
from user_, user_role, wf_step_role
where wf_step_role.role_id = user_role.role_id
and user_role.user_id = user_.user_id
and wf_step_role.step_id = 2))) OR
(SELECT COUNT(*)
FROM org b
WHERE b.org_id in
(select org_id
from user_org
where user_id in
(select user_.user_id
from user_, user_role, wf_step_role
where wf_step_role.role_id = user_role.role_id
and user_role.user_id = user_.user_id
and wf_step_role.step_id = 2))
and rownum < 2
START WITH b.org_id = a.org_id
CONNECT BY PRIOR b.org_id = b.org_parentid) > 0)
order by org_order
在OR后面的不是true就是False
请解释一下这条SQL意思，详细说明一下！
or是短路操作嘛
如果or的左边是true，那就不对右边进行查询了，
如果or的左边是false，才对右边进行查询，
((a.org_id in
(select org_id
from user_org
where user_id in (select user_.user_id
from user_, user_role, wf_step_role
where wf_step_role.role_id = user_role.role_id
and user_role.user_id = user_.user_id
and wf_step_role.step_id = 2)))
是假！
sql 中 只有 true false maybe 3种情况。 count(*)又不能返回NULL, 也就是（count(*)....... ） 〉 n 不可能为maybe
当然是true 或 false
-_-|||你想问什么。。。