Problem Description
As a cute girl, Kotori likes playing Hide and Seek'' with cats particularly.
Under the influence of Kotori, many girls and cats are playingHide and Seek'' together.
Koroti shots a photo. The size of this photo is n×m, each pixel of the photo is a character of the lowercase(from a' toz').
Kotori wants to know how many girls and how many cats are there in the photo.

We define a girl as -- we choose a point as the start, passing by 4 different connected points continuously, and the four characters are exactly girl'' in the order.
We define two girls are different if there is at least a point of the two girls are different.
We define a cat as -- we choose a point as the start, passing by 3 different connected points continuously, and the three characters are exactlycat'' in the order.
We define two cats are different if there is at least a point of the two cats are different.

Two points are regarded to be connected if and only if they share a common edge.

Input
The first line is an integer T which represents the case number.

As for each case, the first line are two integers n and m, which are the height and the width of the photo.
Then there are n lines followed, and there are m characters of each line, which are the the details of the photo.

It is guaranteed that:
T is about 50.
1≤n≤1000.
1≤m≤1000.
∑(n×m)≤2×106.

Output
As for each case, you need to output a single line.
There should be 2 integers in the line with a blank between them representing the number of girls and cats respectively.

Please make sure that there is no extra blank.

Sample Input
3
1 4
girl
2 3
oto
cat
3 4
girl
hrlt
hlca

https://blog.csdn.net/chenshibo17/article/details/79952849

include

#include
Void main() {
Int n,m,case,i=1,count=0;
Char tem [4],ch;
Char cat[]=”cat”;
Char girl[]=”girl”;
Printf(“请输入照片数量：”);
Scanf(“%d”,case);
While(i<=case){
Scanf(“%d”,n);//
Scanf(“”%d”,m);//
For(int p=1;p<=n;p++){
If(m==3){
for(int k=0;k<3;k++){
getchar(ch);
tem[k]=ch;
}
Tem[3]=’\0’;
If(!strcmp(cat,tem)){
Count++;
}
}
If(m==4){
for(int k=0;k<4;k++){
getchar(ch);
tem[k]=ch;
}
If(!strcmp(cat,tem)){
Count++;
}
}
Printf(“%d\n”,count);
}
}
}