利用公式s=1/12-1/22+1/32-1/42……计算直到最后一项的绝对值小于0.000001的s的值
double s = 0; int sign = 1; int div = 12; do { double d = sign / (double)div; s += d; sign = -sign; div += 10; } while (fabs(d) >= 0.00001); printf("%lf", s);