我有一个代码，能不能帮我把里面的swing和awt改成JavaFx，急需。联系QQ3246798340，可rmb报酬

package _4;

import java.util.LinkedList;
import java.util.Queue;
import java.util.Random;
import java.util.Stack;

/**

• 迷宫生成算法和迷宫寻路算法

• @author ygch
  */
  public class Maze {
  private int height;
  private int width;
  private Random r; //随机位置生成器
  private boolean blocked[][];
  boolean[][] visited;//寻路过程中判断某个位置是否已经被访问过
  private Stack path;//寻路过程中保存的路径
  private final int[][] direction={{0, -1}, {1, 0}, {0, 1}, {-1, 0}};

  /**

  • 重构equals函数，方便后面的比较操作 */ @Override public boolean equals(Object obj) { if (this == obj) return true; if (obj == null) return false; if (getClass() != obj.getClass()) return false; Maze other = (Maze) obj; return height == other.height && width == other.width; }

  public Maze(int height, int width) {
  super();
  this.height = height;
  this.width = width;
  //让整个迷宫的大小为奇数，这样可以构造一行路一行墙的迷宫
  if(this.height%2==0) this.height+=1;
  if(this.width%2==0) this.width+=1;
  r = new Random();
  path= new Stack<>();

  //给迷宫四周加上墙
  blocked = new boolean[this.height + 2][this.width + 2];
  visited=new boolean[this.height+2][this.width+2];
  
  // 最左和最右两列置1
  for (int i = 0; i < this.height + 2; i++) {
      blocked[i][0] = true;
      blocked[i][this.width + 1] = true;
  }
  
  // 最上和最下两行置1
  for (int i = 0; i < this.width + 2; i++) {
      blocked[0][i] = true;
      blocked[this.height + 1][i] = true;
  }
  

  }

  public int getHeight()
  {
  return height;
  }

  public int getWidth()
  {
  return width;
  }

部分如上

希望今天早上10点前能发给我