给字典增加新的密钥?

Is it possible to add a key to a Python dictionary after it has been created? It doesn't seem to have an .add() method.

转载于:https://stackoverflow.com/questions/1024847/add-new-keys-to-a-dictionary

>>> d = {'key':'value'}
>>> print(d)
{'key': 'value'}
>>> d['mynewkey'] = 'mynewvalue'
>>> print(d)
{'mynewkey': 'mynewvalue', 'key': 'value'}
dictionary[key] = value

Yeah, it's pretty easy. Just do the following:

dict["key"] = "value"
>>> x = {1:2}
>>> print x
{1: 2}

>>> x.update({3:4})
>>> print x
{1: 2, 3: 4}

I feel like consolidating info about Python dictionaries:

Creating an empty dictionary

data = {}
# OR
data = dict()

Creating a dictionary with initial values

data = {'a':1,'b':2,'c':3}
# OR
data = dict(a=1, b=2, c=3)
# OR
data = {k: v for k, v in (('a', 1),('b',2),('c',3))}

Inserting/Updating a single value

data['a']=1  # Updates if 'a' exists, else adds 'a'
# OR
data.update({'a':1})
# OR
data.update(dict(a=1))
# OR
data.update(a=1)

Inserting/Updating multiple values

data.update({'c':3,'d':4})  # Updates 'c' and adds 'd'

Creating a merged dictionary without modifying originals

data3 = {}
data3.update(data)  # Modifies data3, not data
data3.update(data2)  # Modifies data3, not data2

Deleting items in dictionary

del data[key]  # Removes specific element in a dictionary
data.pop(key)  # Removes the key & returns the value
data.clear()  # Clears entire dictionary

Check if a key is already in dictionary

key in data

Iterate through pairs in a dictionary

for key in data: # Iterates just through the keys, ignoring the values
for key, value in d.items(): # Iterates through the pairs
for key in d.keys(): # Iterates just through key, ignoring the values
for value in d.values(): # Iterates just through value, ignoring the keys

Create a dictionary from 2 lists

data = dict(zip(list_with_keys, list_with_values))

Feel free to add more!

data = {}
data['a'] = 'A'
data['b'] = 'B'

for key, value in data.iteritems():
    print "%s-%s" % (key, value)

results in

a-A
b-B

If you want to add a dictionary within a dictionary you can do it this way.

Example: Add a new entry to your dictionary & sub dictionary

dictionary = {}
dictionary["new key"] = "some new entry" # add new dictionary entry
dictionary["dictionary_within_a_dictionary"] = {} # this is required by python
dictionary["dictionary_within_a_dictionary"]["sub_dict"] = {"other" : "dictionary"}
print (dictionary)

Output:

{'new key': 'some new entry', 'dictionary_within_a_dictionary': {'sub_dict': {'other': 'dictionarly'}}}

NOTE: Python requires that you first add a sub

dictionary["dictionary_within_a_dictionary"] = {}

before adding entries.

The orthodox syntax is d[key] = value, but if your keyboard is missing the square bracket keys you could do:

d.__setitem__(key, value)

In fact, defining __getitem__ and __setitem__ methods is how you can make your own class support the square bracket syntax. See http://www.diveintopython.net/object_oriented_framework/special_class_methods.html

you can create one

class myDict(dict):

    def __init__(self):
        self = dict()

    def add(self, key, value):
        self[key] = value

## example

myd = myDict()
myd.add('apples',6)
myd.add('bananas',3)
print(myd)

gives

>>> 
{'apples': 6, 'bananas': 3}

This popular question addresses functional methods of merging dictionaries a and b.

Here are some of the more straightforward methods (tested in Python 3)...

c = dict( a, **b ) ## see also https://stackoverflow.com/q/2255878
c = dict( list(a.items()) + list(b.items()) )
c = dict( i for d in [a,b] for i in d.items() )

Note: The first method above only works if the keys in b are strings.

To add or modify a single element, the b dictionary would contain only that one element...

c = dict( a, **{'d':'dog'} ) ## returns a dictionary based on 'a'

This is equivalent to...

def functional_dict_add( dictionary, key, value ):
   temp = dictionary.copy()
   temp[key] = value
   return temp

c = functional_dict_add( a, 'd', 'dog' )

This is exactly how I would do it: # fixed data with sapce

data = {}
data['f'] = 'F'
data['c'] = 'C'

for key, value in data.iteritems():
    print "%s-%s" % (key, value)

This works for me. Enjoy!

we can add new keys to dictionary by this way:

Dictionary_Name[New_Key_Name] = New_Key_Value

Here is the Example:

# This is my dictionary
my_dict = {'Key1': 'Value1', 'Key2': 'Value2'}
# Now add new key in my dictionary
my_dict['key3'] = 'Value3'
# Print updated dictionary
print my_dict

Output:

{'key3': 'Value3', 'Key2': 'Value2', 'Key1': 'Value1'}

It has a update method which you can use like this:

dict.update({"key" : "value"})

So many answers and still everybody forgot about the strangely named, oddly behaved, and yet still handy dict.setdefault()

This

value = my_dict.setdefault(key, default)

basically just does this:

try:
    value = my_dict[key]
except KeyError: # key not found
    value = my_dict[key] = default

e.g.

>>> mydict = {'a':1, 'b':2, 'c':3}
>>> mydict.setdefault('d', 4)
4 # returns new value at mydict['d']
>>> print(mydict)
{'a':1, 'b':2, 'c':3, 'd':4} # a new key/value pair was indeed added
# but see what happens when trying it on an existing key...
>>> mydict.setdefault('a', 111)
1 # old value was returned
>>> print(mydict)
{'a':1, 'b':2, 'c':3, 'd':4} # existing key was ignored

Use the subscript assignment operator:

d['x'] = "value"

Don't forget that Python's key can by anything hashable which means bool, int, string even a tuple or any objects hashable.

Let's pretend you want to live in the immutable world and do NOT want to modify the original but want to create a new dict that is the result of adding a new key to the original.

In Python 3.5+ you can do:

params = {'a': 1, 'b': 2}
new_params = {**params, **{'c': 3}}

The Python 2 equivalent is:

params = {'a': 1, 'b': 2}
new_params = dict(params, **{'c': 3})

After either of these:

params is still equal to {'a': 1, 'b': 2}

and

new_params is equal to {'a': 1, 'b': 2, 'c': 3}

There will be times when you don't want to modify the original (you only want the result of adding to the original). I find this a refreshing alternative to the following:

params = {'a': 1, 'b': 2}
new_params = params.copy()
new_params['c'] = 3

or

params = {'a': 1, 'b': 2}
new_params = params.copy()
new_params.update({'c': 3})

Reference: https://stackoverflow.com/a/2255892/514866

I would do it like this. Watch out for the directory[name]=number part.

n = int(raw_input())
directory={}
entry={}
# store the values as if they appear in the stdin
for i in xrange(n):
    name, number = raw_input().split()
    directory[name]=number

#  query the values    
while (True):
    queryname = (str) (raw_input())
    try:
        strdisp = queryname + "=" + directory[queryname]
        print strdisp
    except:
      print 'Not found'

If you're not joining two dictionaries, but adding new key-value pairs to a dictionary, then using the subscript notation seems like the best way.

import timeit

timeit.timeit('dictionary = {"karga": 1, "darga": 2}; dictionary.update({"aaa": 123123, "asd": 233})')
>> 0.49582505226135254

timeit.timeit('dictionary = {"karga": 1, "darga": 2}; dictionary["aaa"] = 123123; dictionary["asd"] = 233;')
>> 0.20782899856567383

However, if you'd like to add, for example, thousands of new key-value pairs, you should consider using the update() method.