C 编程的数字计数函数不能工作超过11位

The following function is supposed to be used to count the number of digits in a number. Unfortunately it doesn't work for numbers with 11 or more digits and I'm not sure why. I feel like it has something to do with the data type but I thought long long int would be fine in this case. Thanks for the help!

long long int getLength(long long int input)
{
  long long int length = 0;

  while(input != 0)
  {
    input /= 10;
    ++length;
  }
  return (length);
}

This may not stand as an answer, but allow me to report output here. Can you double check? It works on my side.

#include "stdio.h"

long long int getLength(long long int input)
{
  long long int length = 0;

  while(input != 0)
  {
    input /= 10;
    ++length;
  }
  return (length);
}

int main()
{
    printf("%lld\n", getLength(12345678901));   // 11
    printf("%lld\n", getLength(123456789012));  // 12
    printf("%lld\n", getLength(1234567890123)); // 13
    printf("%lld\n", getLength(0));             // 0
    printf("%lld\n", getLength(-123));          // 3
}

Platform Windows 10, and gcc --version returns

gcc (x86_64-posix-seh-rev0, Built by MinGW-W64 project) 7.3.0

Question 1: do you really need type long long int to report number of digits?

Question 2: did you correctly use the format specifier %lld in your printf?