Which is the effective way to trim the leading and trailing white spaces of string variable in Go?
转载于:https://stackoverflow.com/questions/22688010/how-to-trim-leading-and-trailing-white-spaces-of-a-string
For example,
package main
import (
"fmt"
"strings"
)
func main() {
s := "\t Hello, World\n "
fmt.Printf("%d %q\n", len(s), s)
t := strings.TrimSpace(s)
fmt.Printf("%d %q\n", len(t), t)
}
Output:
16 "\t Hello, World\n "
12 "Hello, World"
There's a bunch of functions to trim strings in go.
See them there : Trim
Here's an example, adapted from the documentation, removing leading and trailing white spaces :
fmt.Printf("[%q]", strings.Trim(" Achtung ", " "))
For trimming your string, Go's "strings" package have TrimSpace()
, Trim()
function that trims leading and trailing spaces.
Check the documentation for more information.
Just as @Kabeer has mentioned, you can use TrimSpace and here is an example from golang documentation:
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.TrimSpace(" \t\n Hello, Gophers \n\t\r\n"))
}
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.TrimSpace(" \t\n Hello, Gophers \n\t\r\n"))
}
Output: Hello, Gophers
And simply follow this link - https://golang.org/pkg/strings/#TrimSpace