在 Go 中如何将一个 int 值转换为字符串？

i := 123
s := string(i) 

s is 'E', but what I want is "123"

Please tell me how can I get "123".

And in Java, I can do in this way:

String s = "ab" + "c"  // s is "abc"

how can I concat two strings in Go?

Use the strconv package's Itoa function.

For example:

package main

import (
    "strconv"
    "fmt"
)

func main() {
    t := strconv.Itoa(123)
    fmt.Println(t)
}

You can concat strings simply by +'ing them, or by using the Join function of the strings package.

You can use fmt.Sprintf

See http://play.golang.org/p/bXb1vjYbyc for example.

fmt.Sprintf("%v",value);

If you know the specific type of value use the corresponding formatter for example %d for int

More info - fmt

It is interesting to note that strconv.Itoa is shorthand for

func FormatInt(i int64, base int) string

with base 10

For Example:

strconv.Itoa(123)

is equivalent to

strconv.FormatInt(int64(123), 10)

fmt.Sprintf, strconv.Itoa and strconv.FormatInt will do the job. But Sprintf will use the package reflect, and it will allocate one more object, so it's not a good choice.

In this case both strconv and fmt.Sprintf do the same job but using the strconv package's Itoa function is the best choice, because fmt.Sprintf allocate one more object during conversion.

check the benchmark here: https://gist.github.com/evalphobia/caee1602969a640a4530

see https://play.golang.org/p/hlaz_rMa0D for example.

Converting int64:

n := int64(32)
str := strconv.FormatInt(n, 10)

fmt.Println(str)
// Prints "32"