Convert date format yyyy-mm-dd => dd-mm-yyyy [duplicate]

I am trying to convert a date from yyyy-mm-dd to dd-mm-yyyy (but not in SQL); however I don't know how the date function requires a timestamp, and I can't get a timestamp from this string.

How is this possible?

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转载于:https://stackoverflow.com/questions/2487921/convert-date-format-yyyy-mm-dd-dd-mm-yyyy

Use strtotime() and date():

$originalDate = "2010-03-21";
$newDate = date("d-m-Y", strtotime($originalDate));

(see strtotime and date docs on the PHP site).

Edit: Note that this was a quick solution to the original question. For more extensive conversions, you should really be using the DateTime class to parse & format :-)

$timestamp = strtotime(your date variable); 
$new_date = date('d-m-Y', $timestamp);

For more:

click here

Or even shorter:

$new_date = date('d-m-Y', strtotime(your date variable));

You can try strftime function. Something like strftime($time, '%d %m %Y');

Also another obscure possibility:

$oldDate = '2010-03-20'
$arr = explode('-', $oldDate);
$newDate = $arr[2].'-'.$arr[1].'-'.$arr[0];

I don't know if I would use it but still :)

implode('-', array_reverse(explode('-', $date)));

Without date conversion overhead, not sure it'll matter much.

$newDate = preg_replace("/(\d+)\D+(\d+)\D+(\d+)/","$3-$2-$1",$originalDate);

This code works for every date format.

You can change the order of replacement variables such $3-$1-$2 due to your old date format.

If you'd like to avoid strtotime conversion(for example strtotime is not being able to parse your input) you can use,

$myDateTime = DateTime::createFromFormat('Y-m-d', $dateString);
$newDateString = $myDateTime->format('d-m-Y');

or, equivalently:

$newDateString = date_format(date_create_from_format('Y-m-d', $dateString), 'd-m-Y');

You are first giving it the format $dateString is in. Then you are telling it the format you want $newDateString to be in.

Or if the source-format always is "Y-m-d" (yyyy-mm-dd), then just use DateTime:

<?php
$source = '2012-07-31';
$date = new DateTime($source);
echo $date->format('d.m.Y'); // 31.07.2012
echo $date->format('d-m-Y'); // 31-07-2012
?>

Edit: Because this post's answer sometimes gets upvoted, I came back here to kindly ask people not to upvote it anymore. My answer is ancient, not technically correct, and there are several better approaches right here. I'm only keeping it here for historical purposes.

Although the documentation poorly describes the strtotime function, @rjmunro correctly addressed the issue in his comment: it's in ISO format date "YYYY-MM-DD".

Also, even though my Date_Converter function might still work, I'd like to warn that there may be imprecise statements below, so please do disregard them.

The most voted answer is actually incorrect!

PHP strtotime Manual here states that "The function expects to be given a string containing an English date format". What it actually means is that it expects an American US date format, such as "m-d-Y" or "m/d/Y".

That means that a date provided as "Y-m-d" may get misinterpreted by strtotime. You should provide the date in the expected format.

I wrote a little function to return dates in several formats. Use and modify as will. If anyone does turn that into a Class, I'd be glad if that would be shared.

function Date_Converter($date, $locale = "br") {

    # Exception
    if (is_null($date))
        $date = date("m/d/Y H:i:s");

    # Let's go ahead and get a string date in case we've been given a Unix Time Stamp
    if ($locale == "unix")
        $date = date("m/d/Y H:i:s", $date);

    # Separate Date from Time
    $date = explode(" ", $date);

    if ($locale == "br") {
        # Separate d/m/Y from Date
        $date[0] = explode("/", $date[0]);
        # Rearrange Date into m/d/Y
        $date[0] = $date[0][1] . "/" . $date[0][0] . "/" . $date[0][2];
    }

    # Return date in all formats
        # US
        $Return["datetime"]["us"]   = implode(" ", $date);
        $Return["date"]["us"]       = $date[0];
        # Universal
        $Return["time"]         = $date[1];
        $Return["unix_datetime"]    = strtotime($Return["datetime"]["us"]);
        $Return["unix_date"]        = strtotime($Return["date"]["us"]);
        $Return["getdate"]          = getdate($Return["unix_datetime"]);
        # BR
        $Return["datetime"]["br"]   = date("d/m/Y H:i:s", $Return["unix_datetime"]);
        $Return["date"]["br"]       = date("d/m/Y", $Return["unix_date"]);

    # Return
    return $Return;


} # End Function

Given below is PHP code to generate tomorrow's date using mktime() and change its format to dd/mm/yyyy format and then print it using echo.

$tomorrow = mktime(0, 0, 0, date("m"), date("d") + 1, date("Y"));
echo date("d", $tomorrow) . "/" . date("m", $tomorrow). "/" . date("Y", $tomorrow);

date('m/d/Y h:i:s a',strtotime($val['EventDateTime']));

two ways to implement this

1)

$date = strtotime(date); 
$new_date = date('d-m-Y', $date);

2)

$cls_date = new DateTime($date);
echo $cls_date->format('d-m-Y'); 

Use this function to convert from any format to any format

function reformatDate($date, $from_format = 'd/m/Y', $to_format = 'Y-m-d') {
    $date_aux = date_create_from_format($from_format, $date);
    return date_format($date_aux,$to_format);
}