为什么 Java 的 + ,-,* ,/ 复合赋值操作符需要铸造?

Until today, I thought that for example:

i += j;

Was just a shortcut for:

i = i + j;

But if we try this:

int i = 5;
long j = 8;

Then i = i + j; will not compile but i += j; will compile fine.

Does it mean that in fact i += j; is a shortcut for something like this i = (type of i) (i + j)?

转载于:https://stackoverflow.com/questions/8710619/why-dont-javas-compound-assignment-operators-require-casting