如何用循环打印出这幅图

要求：使用者输入行数然后print出相应结果

java版本的

如果问题解决，麻烦点下我回答右边的采纳，谢谢。

 // Q701108.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"

int table[] = {1,5,8,9,10,11,10,8,5,1,-3,-6,-8,-9,-8,-6,-3};
int N = 17;
void out(int n)
{
    if (n > 0)
    {
        for (int j = 0; j < 10; j++) printf(" ");
        for (int j = 0; j < n; j++) printf("*");
        printf("\n");
    }
    else
    {
        for (int j = 0; j < 9 + n; j++) printf(" ");
        for (int j = 0; j < 2 - n; j++) printf("*");
        printf("\n");
    }
}
int _tmain(int argc, _TCHAR* argv[])
{
    printf("input the # of lines:");
    int n;
    scanf("%d", &n);
    for (int i = 0; i < n; i++)
    {
        out(table[i % N]);
    }
    return 0;
}

 #include <iostream>
#include <math.h> 

using namespace std;

int main(){
    float pi = 3.1415926;
    int wave = 10;
    int lines = 17;
    for( int i = 0; i < lines; i++ ){
        int bound = round( sin( pi / 8 * i ) * wave );
        for( int i = -wave; i <= wave; i++ ){
            cout << ( ( bound > 0 ) ? 
                ( ( 0 <= i && i <= bound ) ? "*" : " "):
                ( ( bound <= i && i <= 0 ) ? "*" : " ")
            );
        }
        cout << endl;
    }
} 

修改了一下，用了一个判断区间的小技巧，楼主可以思考一下

#include <iostream>
#include <math.h> 

using namespace std;

int main(){
    float pi = 3.1415926;
    int wave = 10;

    int lines;
    cout << "Input the lines:"; cin >> lines;

    for( int i = 0; i < lines; i++ ){
        int bound = round( sin( pi / 8 * i ) * wave );

        for( int j = -wave; j <= wave; j++ )
            cout << ( (0-j)*(j-bound) >= 0 ? "*" : " " );
        cout << endl;
    }
} 

Java版本

 public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);

        double pi = 3.1415926;
        int wave = 10;

        int lines;
        System.out.println("Input the lines:");
        lines = scan.nextInt();

        for( int i = 0; i < lines; i++ ){
            int bound = (int)Math.round( Math.sin( pi / 8 * i ) * wave );

            for( int j = -wave; j <= wave; j++ )
                System.out.print( ( (0-j)*(j-bound) >= 0 ? "*" : " " ) );
            System.out.println();
        }
    }