编程小白求指导,如何实现如图所示的数据结构,并且统计节点数
python实现链表
首先,定义节点类Node:
class Node:
'''
data: 节点保存的数据
next: 保存下一个节点对象
'''
def __init_(self, data, pnext=None):
self.data = data
self._next = pnext
def __repr__(self):
'''
用来定义Node的字符输出,
print为输出data
'''
return str(self.data)
然后,定义链表类:
链表要包括:
属性:
链表头:head
链表长度:length
方法:
判断是否为空: isEmpty()
def isEmpty(self):
return (self.length == 0
增加一个节点(在链表尾添加): append()
def append(self, dataOrNode):
item = None
if isinstance(dataOrNode, Node):
item = dataOrNode
else:
item = Node(dataOrNode)
if not self.head:
self.head = item
self.length += 1
else:
node = self.head
while node._next:
node = node._next
node._next = item
self.length += 1
删除一个节点: delete()
#删除一个节点之后记得要把链表长度减一
def delete(self, index):
if self.isEmpty():
print "this chain table is empty."
return
if index < 0 or index >= self.length:
print 'error: out of index'
return
#要注意删除第一个节点的情况
#如果有空的头节点就不用这样
#但是我不喜欢弄头节点
if index == 0:
self.head = self.head._next
self.length -= 1
return
#prev为保存前导节点
#node为保存当前节点
#当j与index相等时就
#相当于找到要删除的节点
j = 0
node = self.head
prev = self.head
while node._next and j < index:
prev = node
node = node._next
j += 1
if j == index:
prev._next = node._next
self.length -= 1
修改一个节点: update()
def update(self, index, data):
if self.isEmpty() or index < 0 or index >= self.length:
print 'error: out of index'
return
j = 0
node = self.head
while node._next and j < index:
node = node._next
j += 1
if j == index:
node.data = data
查找一个节点: getItem()
def getItem(self, index):
if self.isEmpty() or index < 0 or index >= self.length:
print "error: out of index"
return
j = 0
node = self.head
while node._next and j < index:
node = node._next
j += 1
return node.data
查找一个节点的索引: getIndex()
def getIndex(self, data):
j = 0
if self.isEmpty():
print "this chain table is empty"
return
node = self.head
while node:
if node.data == data:
return j
node = node._next
j += 1
if j == self.length:
print "%s not found" % str(data)
return
插入一个节点: insert()
def insert(self, index, dataOrNode):
if self.isEmpty():
print "this chain tabale is empty"
return
if index < 0 or index >= self.length:
print "error: out of index"
return
item = None
if isinstance(dataOrNode, Node):
item = dataOrNode
else:
item = Node(dataOrNode)
if index == 0:
item._next = self.head
self.head = item
self.length += 1
return
j = 0
node = self.head
prev = self.head
while node._next and j < index:
prev = node
node = node._next
j += 1
if j == index:
item._next = node
prev._next = item
self.length += 1
清空链表: clear()
def clear(self):
self.head = None
self.length = 0