算法第四版二分法代码运行出现错误

感谢各位大神！
代码是直接从官网保存下来的，在终端运行时出现以下错误提示，不知道是该怎么改啊...

MA:src vicky$ javac BinarySearch.java
MA:src vicky$ java BinarySearch tinyW.txt < tinyT.txt
Exception in thread "main" java.lang.NumberFormatException: For input string: "{\rtf1\ansi\ansicpg936\cocoartf1404\cocoasubrtf470"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
at In.readAllInts(In.java:528)
at BinarySearch.main(BinarySearch.java:93)

源代码如下
/******************************************************************************

• Compilation: javac BinarySearch.java
• Execution: java BinarySearch whitelist.txt < input.txt
• Dependencies: In.java StdIn.java StdOut.java
• Data files: https://algs4.cs.princeton.edu/11model/tinyW.txt
• https://algs4.cs.princeton.edu/11model/tinyT.txt
• https://algs4.cs.princeton.edu/11model/largeW.txt
• https://algs4.cs.princeton.edu/11model/largeT.txt *
• % java BinarySearch tinyW.txt < tinyT.txt
• 50
• 99
• 13 *
• % java BinarySearch largeW.txt < largeT.txt | more
• 499569
• 984875
• 295754
• 207807
• 140925
• 161828
• [367,966 total values]
• ******************************************************************************/

import java.util.Arrays;

/**

• The {@code BinarySearch} class provides a static method for binary
• searching for an integer in a sorted array of integers.
• The indexOf operations takes logarithmic time in the worst case.
• For additional documentation, see Section 1.1 of
• Algorithms, 4th Edition by Robert Sedgewick and Kevin Wayne. *
• @author Robert Sedgewick

• @author Kevin Wayne
  */
  public class BinarySearch {

  /**

  • This class should not be instantiated. */ private BinarySearch() { }

  /**

  • Returns the index of the specified key in the specified array. *
  • @param a the array of integers, must be sorted in ascending order
  • @param key the search key
  • @return index of key in array {@code a} if present; {@code -1} otherwise */ public static int indexOf(int[] a, int key) { int lo = 0; int hi = a.length - 1; while (lo <= hi) { // Key is in a[lo..hi] or not present. int mid = lo + (hi - lo) / 2; if (key < a[mid]) hi = mid - 1; else if (key > a[mid]) lo = mid + 1; else return mid; } return -1; }

  /**

  • Returns the index of the specified key in the specified array.
  • This function is poorly named because it does not give the rank
  • if the array has duplicate keys or if the key is not in the array. *
  • @param key the search key
  • @param a the array of integers, must be sorted in ascending order
  • @return index of key in array {@code a} if present; {@code -1} otherwise
  • @deprecated Replaced by {@link #indexOf(int[], int)}. */ @Deprecated public static int rank(int key, int[] a) { return indexOf(a, key); }

  /**

  • Reads in a sequence of integers from the whitelist file, specified as
  • a command-line argument; reads in integers from standard input;
  • prints to standard output those integers that do not appear in the file. *

  • @param args the command-line arguments
    */
    public static void main(String[] args) {

    // read the integers from a file
    In in = new In(args[0]);
    int[] whitelist = in.readAllInts();

    // sort the array
    Arrays.sort(whitelist);

    // read integer key from standard input; print if not in whitelist
    while (!StdIn.isEmpty()) {
    int key = StdIn.readInt();
    if (BinarySearch.indexOf(whitelist, key) == -1)
    StdOut.println(key);
    }
    }
    }

报错已经说了：java.lang.NumberFormatException: For input string: "{\rtf1\ansi\ansicpg936\cocoartf1404\cocoasubrtf470"，可以看一下输入的格式是否有问题