java远程取文件名！！！

例如： abc_ddd_20170910_01.REQ（顺序不固定就这五块）

取成：  [abc_ddd_];{sysdate-1:yyyymmdd};[_];{string:2};[.REQ]

 Pattern pattern = Pattern.compile("[a-z]+_[a-z]+_");
Matcher matcher = pattern.matcher(文件名);
System.out.println(matcher.group(0)); // abc_ddd_

Pattern pattern = Pattern.compile("\\d{8}"); // 20170910

Pattern pattern = Pattern.compile("\\d+\\.[A-Z]{3}"); // 01.REQ

 因为你实在只有一条数据的例子，所以我可以写给你，但是不保证通用性

Pattern pattern = Pattern.compile("[a-z]+_[a-z]+_");
Matcher matcher = pattern.matcher(文件名);
string s1 = matcher.group(0);
pattern = Pattern.compile("\\d{8}");
matcher = pattern.matcher(文件名);
string s2 = matcher.group(0);
pattern = Pattern.compile("\\d+\\.[A-Z]{3}");
matcher = pattern.matcher(文件名);
string s3 = matcher.group(0);
string result = "["+s1+"];{sysdate-1:"+s2+"};[_];{string:2};["+s3.split(".")[1]+"]"

 Pattern pattern = Pattern.compile("[a-z]+(_[a-z])*");
Matcher matcher = pattern.matcher(文件名.split(".")[0]);
string s1 = matcher.group(0);
pattern = Pattern.compile("\\d{8}");
matcher = pattern.matcher(文件名);
string s2 = matcher.group(0);
pattern = Pattern.compile("\\d+\\.[A-Za-z]{3}");
matcher = pattern.matcher(文件名);
string s3 = matcher.group(0);
string result = "["+s1+"];{sysdate-1:"+s2+"};[_];{string:2};["+s3.split(".")[1]+"]";

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