[#assign totalCount=(pagedList.totalPages)?number/]
[#assign begin1= 1/]
[#assign end1= 3/]
[#assign begin2= 0/]
[#assign end2= 0/]
[#assign begin3= totalCount-2/]
[#assign end3= totalCount/]
[#if page<=end1+2]
[#if page==totalCount]
[#assign end1= totalCount/]
[#else]
[#assign end1= page+1/]
[/#if]
[#elseif page>end1+2 &&page<=begin3-2]
[#assign begin2= page-1/]
[#assign end2= page+1/]
[#elseif page > begin3-2 &&page<=end3]
[#assign begin3= page-1/]
[/#if]
<div class="page">
<div class="p_btns">
<span class="total_count">共${pagedList.getTotalElements()}条数据 当前 ${page}页 共 ${end3}页 </span>
<a class="disabled" href="${paging(1)}">首页</a><a class="disabled" href="[#if page>1]${paging(page-1)}[#else]javascript:void(0)[/#if]">上一页</a>
[#list begin1 ..end1 as t]
[#if page==t]
<a href="javascript:void(0)" style="background-color:#bbb;"><span>${page}</span></a>
[#else]
<a href="${paging(t)}">${t}</a>
[/#if]
[/#list]
[#if begin2!=0 && end2!=0]
...
[#list begin2 ..end2 as t]
[#if page==t]
<a href="javascript:void(0)" style="background-color:#bbb;"><span>${page}</span></a>
[#else]
<a href="${paging(t)}">${t}</a>
[/#if]
[/#list]
[/#if]
[#if begin3 > end2 & begin3 > end1]
...
[#list begin3 ..end3 as t]
[#if page==t]
<a href="javascript:void(0)" style="background-color:#bbb;"><span>${page}</span></a>
[#else]
<a href="${paging(t)}">${t}</a>
[/#if]
[/#list]
[/#if]
<a target="_self" href="[#if page < pagedList.totalPages]${paging(page+1)}[#else]javascript:void(0)[/#if]">下一页</a>
<a target="_self" href="${paging(pagedList.totalPages)}">末页</a>
</div>
</div>
冒昧问一句,你这是什么编程语言?从来没有见过,感觉还蛮厉害的。然后猜的没错的话,判断是否显示3的那个按钮,条件语句是 [#if begin3 > end2 & begin3 > end1]这个吧?根据前面的声明[#assign begin3= totalCount-2/] [#assign end3= totalCount/],begin3=1,end3=3,end2=0,end1=3,前面if语句的结果是false,是不会执行的吧。如果可以调试的话,楼主还是调试看下跳进了if里面吗
同问 你这是什么编程语言
什么语言,单片机编程?