连续的整数转为字符串输出

input [1, 2, 3, 5, 6, 8]
output ["123", "56', "8"]代码实现

 int n = arr[0];
for (int i = 1; i < n; i++)
{
if (arr[i] == arr[i - 1] + 1) { n *= 10; n += arr[i]; }
else
{
printf("%d", n);
n = arr[i];
}
}

用itoa()方法将整数转为字符串