数据库字段为date,记录几个日期,
然后用DateDiff("d",2017-9-18,date)'算出了距离几天还有XXX天
如何以这个XXX天排序输出结果
图二是正常输出截图
如何按照提醒日排序?
SELECT id,datediff("d",#2017-9-18#,[date]) from [date] order by datediff("d",#2017-9-18#,[date]) desc
如果是距离当前日期#。。。#改为 now
SELECT id,datediff("d",now,[date]) from [date] order by datediff("d",now,[date]) desc
order by DateDiff("d",2017-9-18,date) desc