代码如下：
function JSONToCSVConvertor(JSONData, ReportTitle, ShowLabel) {
//If JSONData is not an object then JSON.parse will parse the JSON string in an Object
var arrData = typeof JSONData != 'object' ? JSON.parse(JSONData)
: JSONData;
var CSV = '';
//Set Report title in first row or line
//CSV += ReportTitle + '\r\n\n';
//This condition will generate the Label/Header
if (ShowLabel) {
var row = "";
//This loop will extract the label from 1st index of on array
/*for ( var index in arrData[0]) {
//Now convert each value to string and comma-seprated
row += index + ',';
} */
row = row.slice(0, -1);
//append Label row with line break
CSV += row + '\r\n';
}
//1st loop is to extract each row
for (var i = 0; i < arrData.length; i++) {
var row = "";
//2nd loop will extract each column and convert it in string comma-seprated
for ( var index in arrData[i]) {
row += '"' + arrData[i][index] + '",';
}
row=row.slice(0, row.length-1);
//add a line break after each row
CSV += row + '\r\n';
}
if (CSV == '') {
alert("Invalid data");
return;
}
//Generate a file name
var fileName = "考勤结果";
//this will remove the blank-spaces from the title and replace it with an underscore
fileName += ReportTitle.replace(/ /g, "_");
//Initialize file format you want csv or xls
//alert(CSV);
var uri = 'data:text/csv;charset=utf-8,\uFEFF' + encodeURI(CSV);
// Now the little tricky part.
// you can use either>> window.open(uri);
// but this will not work in some browsers
// or you will not get the correct file extension
//this trick will generate a temp tag
var link = document.createElement("a");
link.href = uri;
//set the visibility hidden so it will not effect on your web-layout
link.style = "visibility:hidden";
link.download = fileName + ".xls";
//this part will append the anchor tag and remove it after automatic click
document.body.appendChild(link);
link.click();
document.body.removeChild(link);
}
你是直接在浏览器使用JS导出Excel吗？ 我对datagrid不熟悉，我也经常做报表的导出，我一般做法是在后台定义一个导出数据工具类，专门写IO导出，前台把JSON结构传给后台，让后台导出。
因为JS对文件的操作基本很弱，除非有第三方的插件，但是你难免保证所有的浏览器都支持。 方法是很多的，看你怎么选择