1-servlet验证码
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
response.setContentType("image/jpeg");
response.setHeader("Pragma", "No-cache");
response.setHeader("Cache-Control", "no-cache");
response.setDateHeader("Expires", 0);
HttpSession session = request.getSession();
// 在内存中创建图象
int width = 75, height = 25;
BufferedImage image = new BufferedImage(width, height,
BufferedImage.TYPE_INT_RGB);
// 获取图形上下文
Graphics g = image.getGraphics();
// 生成随机类
Random random = new Random();
// 设定背景色
g.setColor(getRandColor(200, 250));
g.fillRect(0, 0, width, height);
// 设定字体
g.setFont(new Font("Times New Roman", Font.PLAIN, 24));
// 画边框
g.setColor(getRandColor(160, 200));
g.drawRect(0, 0, width - 1, height - 1);
// 随机产生155条干扰线,使图象中的认证码不易被其它程序探测到
g.setColor(getRandColor(160, 200));
for (int i = 0; i < 155; i++) {
int x = random.nextInt(width);
int y = random.nextInt(height);
int xl = random.nextInt(12);
int yl = random.nextInt(12);
g.drawLine(x, y, x + xl, y + yl);
}
// 取随机产生的认证码(4位数字)
String sRand = "";
for (int i = 0; i < 4; i++) {
String rand = String.valueOf(random.nextInt(10));
sRand += rand;
// 将认证码显示到图象中
g.setColor(new Color(20 + random.nextInt(110), 20 + random
.nextInt(110), 20 + random.nextInt(110)));
// 调用函数出来的颜色相同,可能是因为种子太接近,所以只能直接生成
g.drawString(rand, 13 * i + 14, 20);
}
// 将认证码存入SESSION
session.setAttribute("vcode", sRand);
// 图象生效
g.dispose();
// 输出图象到页面
ImageIO.write(image, "JPEG", response.getOutputStream());
}
2-后台校验验证码
String checkCode = StaticMethod.null2String(request.getParameter("checkCode"));
if(!vcode.equals(checkCode)) {
loginErrorReturn(request, response, "CheckCodeErrorException");
return mapping.findForward("relogin");
}
3-前台页面
String checkCode = StaticMethod.null2String(request.getParameter("checkCode"));
if(!vcode.equals(checkCode)) {
loginErrorReturn(request, response, "CheckCodeErrorException");
return mapping.findForward("relogin");
}
如何在后台判断验证码错误后刷新验证码
前台用ajax判断一下,然后在调用一下验证码的controller就行了吧