求解一个Java 基础问题!

 List<String> list = new ArrayList<String>();

list的数据

 [615, FAULT_SYMPTOM, 1, 615, FAULT_SYMPTOM, 663, 615, FAULT_SYMPTOM, 821, 615, FAULT_SYMPTOM, 1160, 615, FAULT_SYMPTOM, 1161, 615, FAULT_SYMPTOM, 1162, 615, FAULT_SYMPTOM, 1220, 615, FAULT_SYMPTOM, 1241, 615, FAULT_SYMPTOM, 722, 615, FAULT_SYMPTOM, 880, 813, FAULT_SYMPTOM, 1, 813, FAULT_SYMPTOM, 663, 813, FAULT_SYMPTOM, 821, 813, FAULT_SYMPTOM, 1160, 813, FAULT_SYMPTOM, 1161, 813, FAULT_SYMPTOM, 1162, 813, FAULT_SYMPTOM, 1220, 813, FAULT_SYMPTOM, 1241, 813, FAULT_SYMPTOM, 722, 813, FAULT_SYMPTOM, 880, 834, FAULT_SYMPTOM, 1, 834, FAULT_SYMPTOM, 663, 834, FAULT_SYMPTOM, 821, 834, FAULT_SYMPTOM, 1160, 834, FAULT_SYMPTOM, 1161, 834, FAULT_SYMPTOM, 1162, 834, FAULT_SYMPTOM, 1220, 834, FAULT_SYMPTOM, 1241, 834, FAULT_SYMPTOM, 722, 834, FAULT_SYMPTOM, 880]

想把这数据转成下面类似的格式,就是3个一行的

 615, FAULT_SYMPTOM, 1
 615, FAULT_SYMPTOM, 663
 ......

求解决方法,谢谢!(基础不好,勿喷!)

你问题都不清楚,只是转成换行显示(每三个添加一个换行符)?还是?

控制台打印格式 还是String[]数组格式?

public static void main(String[] args) {
        String a[]={"615", "FAULT_SYMPTOM", "1", "615", "FAULT_SYMPTOM", "615", "615", "FAULT_SYMPTOM", "615", "615", "FAULT_SYMPTOM", "615", "615", "FAULT_SYMPTOM"};
        List<String> list=Arrays.asList(a);
        for(int i=0;i<list.size()-3;i++){
            System.out.println(list.get(i)+","+list.get(i+1)+","+list.get(i+2));
        }
    }

list不提供换行,如果想实现输出后显示成3个一行的话,可以循环输出,没输出三个元素,就输出一个换行符。

做一个循环,每当是三的倍数时,换行就可以了
int count = 0;
for(String str : list){
count ++;
System.out.print(str);
if(count %3 == 0){
System.out.println();
}
}

完美解决你的问题。

好办.思路:对字符串列表集合对3取余,从前到后,每3个数重新作为一个列表,加入到一个最终列表集resList中,实现如下
List<List<String>>resList=new ArrayList<List<String>>();
List<String>res=new ArrayList<String>();
for(int i=0;i<list.size();i++){
    ifi(i%3==0){
        resList.add(res);
        res=new ArrayList<String>();
        res.add(list[i])
    }
    else{
        res.add(list[i]);
    }
}
//结果集[[615, FAULT_SYMPTOM, 1],[615, FAULT_SYMPTOM, 1]...    ....]

int length=list.size();
for(int i=0;i<length-3;i=i+3){
System.out.println(list.get(i)+","+list.get(i+1)+","+list.get(i+2));
}