假如有一个未知类型，枚举可以走default判断吗？

系统做对接，2个系统字典不一致，有时候还有些脏数据，转换时容易出错，有没有办法在遇到脏速度的情况下使用default

/**
 * 常住类型
 */
public enum Household {
    household_01(1, "户籍"),
    household_02(2, "非户籍");

    private int index;
    private String name;

    Household(int index, String name) {
        this.index = index;
        this.name = name;
    }

    public int getIndex() {
        return index;
    }

    public String getName() {
        return name;
    }

    private static final Map<Integer, Household> lookup_int = new HashMap<>();

    static {
        for (Household e : EnumSet.allOf(Household.class)) {
            lookup_int.put(e.getIndex(), e);
        }
    }

    public static Household find(int index) {
        Household value = lookup_int.get(index);
        if (value == null) {
            return null;
        }
        return value;
    }
}

https://bbs.csdn.net/topics/392183589

枚举类型有自己的集合访问方法，建议使用如下方式

/**
 * 常住类型
 */
public enum Household {
    household_01(1, "户籍"),
    household_02(2, "非户籍");

    private int index;
    private String name;

    Household(int index, String name) {
        this.index = index;
        this.name = name;
    }

    public int getIndex() {
        return index;
    }

    public String getName() {
        return name;
    }

    public static Household find(int index) {
        for(Household value:values()){
            if ((value.getIndex() == index)) {
                return value;
            }
        }
                // 匹配不到则返回一个默认值
        return household_01;
    }
}