#include
int main(void)
{
struct student {
int num;
char name[19];
double score;
};
int i,k,N;
scanf("%d",&N);
for(i=0;i {
struct student s[3];
struct student *p;
for(k=0;k scanf("%d%s%lf",&s[k].num,&s[k].name,&s[k].score);
p = &s[k];
}
for(k=0;k printf("%d\t%-20s%lf\n",s[k].num,s[k].name,s[k].score);
}
for(k=0;k printf("%d\t%-20s%lf\n",p->num,p->name,p->score);
}
}
return 0;
}
编译器显示:Your Code: In function 'main':
Your Code:17:19: warning: format '%s' expects argument of type 'char ', but argument 3 has type 'char ()[19]' [-Wformat=]
scanf("%d%s%lf",&s[k].num,&s[k].name,&s[k].score);
^
0:编译失败,请检查源代码!
请问如何解决这个问题?谢谢各位好心人!急急急!!!
scanf("%d%s%lf",&s[k].num,&s[k].name,&s[k].score);
应为:
scanf("%d%s%lf",&s[k].num,s[k].name,&s[k].score);
看一下结构体中name的定义:
char name[19]; //数组名name就是数组的首地址,所以用%s读入时,不用再加取地址运算符&。
用心回答每个问题,如果有帮助,请采纳答案好吗,谢谢~~~
提问显示好像有些问题
#include
int main(void)
{
struct student {
int num;
char name[19];
double score;
};
int i,k,N;
scanf("%d",&N);
for(i=0;i {
struct student s[3];
struct student *p;
for(k=0;k scanf("%d%s%lf",&s[k].num,&s[k].name,&s[k].score);
p = &s[k];
}
for(k=0;k printf("%d\t%-20s%lf\n",s[k].num,s[k].name,s[k].score);
}
for(k=0;k printf("%d\t%-20s%lf\n",p->num,p->name,p->score);
}
}
return 0;
}
编译器显示:Your Code: In function 'main':
Your Code:17:19: warning: format '%s' expects argument of type 'char ', but argument 3 has type 'char ()[19]' [-Wformat=]
scanf("%d%s%lf",&s[k].num,&s[k].name,&s[k].score);
^
0:编译失败,请检查源代码!
请问如何解决这个问题?谢谢各位好心人!急急急!!!
for(i=0;i小于N;i++)
for(k=0;k小于3;k++)