python中用正则抽取第一个或第二个#前的数字

try

 pattern =re.compile('([^#]+)#([^#]+)#([^#]+)')
 match = pattern.search('123#456#789')

 match.group(1)
 match.group(2)
 match.group(3)

try

 pattern =re.compile('[^(#0-9]*([0-9]+)#[^#0-9]*([0-9]+)#[^#]+')
 match = pattern.search('汉字1#a456#789')
 match.group(1)
 match.group(2)