#include<iostream>
#include<vector>
#include<unordered_map>
#include<algorithm>
using namespace std;
class Solution {
public:
vector<vector<int>> For4Sum(vector<int> &nums,int target) {
vector<vector<int>> result;
unordered_map<int,vector<pair<int,int>>> map;
sort(nums.begin(), nums.end());
if (nums.size() < 4) return result;
for (int i = 0; i < nums.size()-1; i++) {
for (int j = i + 1; j < nums.size(); i++) {
map[nums[i]+nums[j]].push_back(pair<int,int>(i,j));
}
}
for (int i = 0; i < nums.size() - 1; i++) {
for (int j = 0; j < nums.size(); i++) {
int key = target - nums[i] - nums[j];
if (map.find(key) != map.end()) {
for (int k = 0; k < map[key].size(); k++) {
if (i < map[key][k].first) {
result.push_back({ nums[i], nums[j], nums[map[key][k].first],nums[map[key][k].second] });
}
}
}
}
}
sort(result.begin(), result.end());
result.erase(unique(result.begin(),result.end()),result.end());
return result;
}
};
int main() {
Solution a;
vector<int> test;
int target;
int temp = 0;
cout << "input target" << endl;
cin >> target;
cout << "input nums" << endl;
while (cin >> temp) {//ctrl+z
test.push_back(temp);
}
vector<vector<int>> result;
result=a.For4Sum(test, target);
for (int i = 0; i < result.size(); i++) {
for (int j = 0; j < result[i].size(); j++)
cout << result[i][j] << " " << endl;
cout << endl;
}
system("pause");
return 0;
}
你的for循环里写的好像全是i++。。。
自己出来了,是i j问题,有2个循环那里,j写成了i。改好后就可以跑了,哈哈哈哈。这是我写的4个数之和。leetcode的题目,欢迎参考讨论!
#include<iostream>
#include<vector>
#include<unordered_map>
#include<algorithm>
using namespace std;
class Solution {
public:
vector<vector<int>> For4Sum(vector<int> &nums,int target) {
vector<vector<int>> result;
unordered_map<int,vector<pair<int,int>>> map;
sort(nums.begin(), nums.end());
if (nums.size() < 4) return result;
for (int i = 0; i < nums.size()-1; i++) {
for (int j = i + 1; j < nums.size(); j++) {
map[nums[i]+nums[j]].push_back(pair<int,int>(i,j));
}
}
for (int i = 0; i < nums.size() - 1; i++) {
for (int j = 0; j < nums.size(); j++) {
int key = target - nums[i] - nums[j];
if (map.find(key) != map.end()) {
for (int k = 0; k < map[key].size(); k++) {
if (i < map[key][k].first) {
result.push_back({ nums[i], nums[j], nums[map[key][k].first],nums[map[key][k].second] });
}
}
}
}
}
sort(result.begin(), result.end());
result.erase(unique(result.begin(),result.end()),result.end());
return result;
}
};
int main() {
Solution a;
vector<int> test;
int target;
int temp = 0;
cout << "input target" << endl;
cin >> target;
cout << "input nums" << endl;
while (cin >> temp) {//ctrl+z
test.push_back(temp);
}
vector<vector<int>> result;
result=a.For4Sum(test, target);
for (int i = 0; i < result.size(); i++) {
for (int j = 0; j < result[i].size(); j++)
cout << result[i][j] << " " ;
cout << endl;
}
system("pause");
return 0;
}
#include<iostream>
#include<vector>
#include<unordered_map>
#include<algorithm>
using namespace std;
class Solution {
public:
vector<vector<int>> For4Sum(vector<int> &nums,int target) {
vector<vector<int>> result;
unordered_map<int,vector<pair<int,int>>> map;
sort(nums.begin(), nums.end());
if (nums.size() < 4) return result;
for (int i = 0; i < nums.size()-1; i++) {
for (int j = i + 1; j < nums.size(); i++) {
map[nums[i]+nums[j]].push_back(pair<int,int>(i,j));
}
}
for (int i = 0; i < nums.size() - 1; i++) {
for (int j = 0; j < nums.size(); i++) {
int key = target - nums[i] - nums[j];
if (map.find(key) != map.end()) {
for (int k = 0; k < map[key].size(); k++) {
if (i < map[key][k].first) {
result.push_back({ nums[i], nums[j], nums[map[key][k].first],nums[map[key][k].second] });
}
}
}
}
}
sort(result.begin(), result.end());
result.erase(unique(result.begin(),result.end()),result.end());
return result;
}
};
int main() {
Solution a;
vector<int> test;
int target;
int temp = 0;
cout << "input target" << endl;
cin >> target;
cout << "input nums" << endl;
while (cin >> temp) {//ctrl+z
test.push_back(temp);
}
vector<vector<int>> result;
result=a.For4Sum(test, target);
for (int i = 0; i < result.size(); i++) {
for (int j = 0; j < result[i].size(); j++)
cout << result[i][j] << " " << endl;
cout << endl;
}
system("pause");
return 0;
}
第二个循环j忘记i+1,然后要从小到大排序的话,经过测试,一下是最终版。我觉得我写的比网上的那个好些 哈哈哈。
题目:
Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target.
Note:
1.Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie, a≤b≤c≤d)
2.The solution set must not contain duplicate quadruplets.
For example, given array S = {1 0 -1 0 -2 2}, and target = 0.
A solution set is:
(-1, 0, 0, 1)
(-2, -1, 1, 2)
(-2, 0, 0, 2)
这是我写的:
#include<iostream>
#include<vector>
#include<unordered_map>
#include<algorithm>
using namespace std;
class Solution {
public:
vector<vector<int>> For4Sum(vector<int> &nums,int target) {
vector<vector<int>> result;
unordered_map<int,vector<pair<int,int>>> map;
sort(nums.begin(), nums.end());
if (nums.size() < 4) return result;
for (int i = 0; i < nums.size()-1; i++) {
for (int j = i + 1; j < nums.size(); j++) {
map[nums[i]+nums[j]].push_back(pair<int,int>(i,j));
}
}
for (int i = 0; i < nums.size() - 1; i++) {
for (int j = i+1; j < nums.size(); j++) {
int key = target - nums[i] - nums[j];
if (map.find(key) != map.end()) {
for (int k = 0; k < map[key].size(); k++) {
if ( j < map[key][k].first) {
result.push_back({ nums[i], nums[j], nums[map[key][k].first],nums[map[key][k].second] });
}
}
}
}
}
sort(result.begin(), result.end());
result.erase(unique(result.begin(),result.end()),result.end());
return result;
}
};
int main() {
Solution a;
vector<int> test;
int target;
int temp = 0;
cout << "input target" << endl;
cin >> target;
cout << "input nums" << endl;
while (cin >> temp) {//ctrl+z
test.push_back(temp);
}
vector<vector<int>> result;
result=a.For4Sum(test, target);
for (int i = 0; i < result.size(); i++) {
for (int j = 0; j < result[i].size(); j++)
cout << result[i][j] << " ";
cout << endl;
}
system("pause");
return 0;
}
这是网上的版本:
class Solution {
public:
vector<vector<int> > fourSum(vector<int> &nums, int target) {
vector<vector<int>> result;
if (nums.size() < 4) return result;
sort(nums.begin(), nums.end());
unordered_map<int, vector<pair<int, int> > > cache;
for (size_t a = 0; a < nums.size(); ++a) {
for (size_t b = a + 1; b < nums.size(); ++b) {
cache[nums[a] + nums[b]].push_back(pair<int, int>(a, b));
}
}
for (int c = 0; c < nums.size(); ++c) {
for (size_t d = c + 1; d < nums.size(); ++d) {
const int key = target - nums[c] - nums[d];
if (cache.find(key) == cache.end()) continue;
const auto& vec = cache[key];
for (size_t k = 0; k < vec.size(); ++k) {
if (c <= vec[k].second)
continue; // 有重叠
result.push_back( { nums[vec[k].first],
nums[vec[k].second], nums[c], nums[d] });
}
}
}
sort(result.begin(), result.end());
result.erase(unique(result.begin(), result.end()), result.end());
return result;
}
};