java8 lambda 这个该怎么写

有会用java8的 stream()写法吗. 实现下面这样的.

                String[] arrs = {"A", "B", "C", "D", "E", "F"};

        List<String> as = new LinkedList<>();
        List<String> bs = new LinkedList<>();
        int i = 0;
        for (String arr : arrs) {
            i++;
            if (i % 2 == 0) {
                as.add(arr);
            } else {
                bs.add(arr);
            }
        }

java的不会，C#的给你写一个，思路是将原始数据编号，然后根据编号的奇数偶数分组
C#写法

 string[] arrs = {"A", "B", "C", "D", "E", "F"};
var query = arrs.Select((x, i) => new {x , i}).GroupBy(x => x.i % 2).Select(x => x.Select(y => y.x).ToList()).ToArray();
var as = query[0];
var as = query[1];

            String[] arrs = {"A", "B", "C", "D", "E", "F"};
    List<String> as = new LinkedList<>();
    List<String> bs = new LinkedList<>();
    final int[] i = {0};
    Arrays.stream(arrs).forEach(a -> {
        i[0]++;
        if (i[0] % 2 == 0) {
            as.add(a);
        } else {
            bs.add(a);
        }
    });

这种不是随便百度就能知道的么？

 String[] arrs = {"A", "B", "C", "D", "E", "F"};
    List<String> as = new LinkedList<>();
    List<String> bs = new LinkedList<>();
    final int[] i = {0};
    Arrays.asList(arrs).stream().forEach(a -> {
        i[0]++;
        if (i[0] % 2 == 0) {
            as.add(a);
        } else {
            bs.add(a);
        }
    });

我这儿有一种方法

    List<String> list = Arrays.asList("A", "B", "C", "D", "E", "F");
    List<String> as = list.stream().filter(s->list.indexOf(s) % 2 == 1).collect(Collectors.toList());
    List<String> bs = list.stream().filter(s->list.indexOf(s) % 2 == 0).collect(Collectors.toList());