Fibonacci数列的递推公式为Fn=Fn-1 + Fn-2其中F1=F2=1 求Fn除以10007的余数是多少
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long int fibo(long int a)
{
if(a <= 2)
{
return 1;
}
else
{
return fibo(a - 1) + fibo(a - 2);
}
}
int main()
{
long int a;
while(scanf("%d",&a) != EOF)
{
printf("%d\n",fibo(a));
}
return 0;
}