main()
{
float a, b, c, d, x1, x2, q, m, n;
printf("please input a,b,c\n");
scanf("%f,%f,%f,"&a, &b, &c);
d = b*b - 4 * a * c;
if
(d >= 0)
{
q = sqrt(d); /*求实根*/
x1 = (-b + q) / (2 * a);
x2 = (-b - q) / (2 * a);
printf("x1=%.2f,x2=%.2f", x1, x2);
}
else
{
m = -b / (2 * a); /*求实部*/
n = sqrt(-d) / (2 * a); /*求虚部*/
printf("x1=%.2f+%.2fi", m, n);
printf("x1=%.2f-%.2fi", m, n);
}
}
VS2015求解一元二次方程时,第五行scanf("%f,%f,%f,"&a, &b, &c);提示表达式必须具有整数或未区分范围的枚举类型
scanf("%f,%f,%f,"&a, &b, &c);改成
scanf("%f,%f,%f",&a, &b, &c);试下,逼死强迫症。
cpp不就好啦~~
#include<iostream>
using namespace std;
int main()
{
cout<<a<<b<<c<<endl;
}