Ajax 返回的json数组解析

[
{"from":"www.baidu.com","musci":"china","type":"Classics"},
{"from":"www.baidu.com","musci":"japen","type":"Country "},
{"from":"www.baidu.com","musci":"Americ","type":"Hip-Hop"},
{"from":"www.baidu.com","musci":"Russia","type":"Jazz"},
{"from":"www.baidu.com","musci":"Korea","type":"Pop"},
]
想循环获得里面的from的值，用了eval转对象。解析不了，请大神帮帮忙

能弹出。

 <script type="text/javascript">
        function test(){
            var a = '[{"from":"www.baidu.com","musci":"china","type":"Classics"},{"from":"www.baidu.com","musci":"japen","type":"Country "},{"from":"www.baidu.com","musci":"Americ","type":"Hip-Hop"},{"from":"www.baidu.com","musci":"Russia","type":"Jazz"},{"from":"www.baidu.com","musci":"Korea","type":"Pop"},]';
            //alert(a);

            a= eval('('+a+')');
            for(var i = 0 ;i<a.length;i++){
                alert(a[i].from);
            }
        }
        window.onload = test;
    </script>

参考
http://blog.csdn.net/zy_281870667/article/details/50484876

文中的第六条，取出来的是数组，用for循环遍历即可

eval是js的运行函数，也是json字符串转json对象函数

建议使用jquery的 parseJSON函数转换

 dada= eval("("+data+")");
for(var i=0,i<data.length;i++){
    var from里的值 = data[i].form;
}

String str = "[{\"from\":\"www.baidu.com\",\"musci\":\"china\",\"type\":\"Classics\"},{\"from\":\"www.baidu.com\",\"musci\":\"japen\",\"type\":\"Country \"},{\"from\":\"www.baidu.com\",\"musci\":\"Americ\",\"type\":\"Hip-Hop\"},{\"from\":\"www.baidu.com\",\"musci\":\"Russia\",\"type\":\"Jazz\"},{\"from\":\"www.baidu.com\",\"musci\":\"Korea\",\"type\":\"Pop\"},]";
JSONArray array = JSONArray.fromObject(str);
for (int i = 0; i < array.size(); i++) {
JSONObject obj = array.getJSONObject(i);
System.out.println(obj.get("from") + "\t" + obj.get("musci") + "\t" + obj.get("type"));
}

这个问题有很多解决办法啊，如果你有用js框架，都有这些方法。其实思想就是：把它看成一个对象数组，然后在用循环遍历即可。

你的确认ajax得到的是字符串而不是已经为json对象（如用jquery，dataType指定为json，回调中的参数已经是json对象，不需要再eval），已经为对象直接遍历就行

    var s = '[\
    {"from":"www.baidu.com","musci":"china","type":"Classics"},\
    {"from":"www.baidu.com","musci":"japen","type":"Country "},\
    {"from":"www.baidu.com","musci":"Americ","type":"Hip-Hop"},\
    {"from":"www.baidu.com","musci":"Russia","type":"Jazz"},\
    {"from":"www.baidu.com","musci":"Korea","type":"Pop"},\
    ]';
    var o = eval('(' + s + ')');
    for(var i=0;i<o.length;i++)alert(o[i].from)

谢谢各位大神们，小弟感激学习了。回答的都可以实现

我正好同问，也遇到过类似的问题，多谢提问和各位大神回答