JS调用controller的 useradd 路径应该怎么写。试了好几次都不对。
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<form action="" method="post">
<table align="center">
<tr>
<td><input type="hidden" id="inputid" name="userName" value="${user.id }" readonly="readonly" /></td>
</tr>
<tr>
<td>用户名:</td>
<td><input type="text" name="userName" value="${user.userName }" /></td>
<td>(*不可为空*)</td>
</tr>
<tr>
<td>密码:</td>
<td><input type="password" name="password" value="${user.password }" /></td>
<td>(*不可为空*)</td>
</tr>
<tr>
<td>年龄:</td>
<td><input type="text" name="age" size="2" value="${user.age }" /></td>
</tr>
<tr>
<td><input type="submit" value="提交" onclick="form1()"/></td>
</tr>
</table>
</form>
第一种:
<---form id='formTable' action="" method="post"-->
<---input type="button" value="提交" onclick="form1()"/>
function form1(){
$("formTable").ajaxSubmit({
url:path+'/user/userupdate.do',
type:"post",
data:{},
success:function(data){
alert("添加成功");
}
});
}
第二种:
<---form id='formTable' action="<%=path%>/user/userupdate.do" method="post"-->
<---input type="submit" value="提交" />
把提交的type改成button试试