SpringMVC一直报404，实在找不出问题

环境是eclipse+maven

你不懂springmvc的跳转流程吗？

第一点 你把第二张图40行的改成 “/” ，
第二点 把index.jsp放到WebRoot下试试

工程名是不是设置了？
web.xml 全帖出来

  <?xml version="1.0" encoding="UTF-8"?>

xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
Archetype Created Web Application

encodingFilter
/*

<servlet>
    <servlet-name>SpringMVC</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:spring-mvc.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
    <async-supported>true</async-supported>
</servlet>
<servlet-mapping>
    <servlet-name>SpringMVC</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
<welcome-file-list>
    <welcome-file>/index.jsp</welcome-file>
</welcome-file-list>
</web-app>  

少了元数据扫描路径吧

  <!-- 元数据扫描 -->  
     <context:component-scan base-package="com.javen.*"></context:component-scan>

context:component-scan base-package="com.javen.controller"，这个com.javen.controller不就是我的路径了吗亲

xml上面有加这个吗

 <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans"  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"   xmlns:context="http://www.springframework.org/schema/context"   xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd  http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"     default-lazy-init="false">  

你们老师没告诉你可以不在类上写注解，但是方法要写@RequestMapping嘛！