Java 中将Timestamp 转换成Json后

 Timestamp timestamp = Timestamp.valueOf("2016-06-06 12:00:00");
        JSONObject jsonObject = JSONObject.fromObject(timestamp);
        System.out.println(jsonObject);

输出值为：

 'pickdate'：{"date":15,"day":1,"hours":12,"minutes":0,"month":1,"nanos":0,"seconds":0,"time":571896000000,"timezoneOffset":-480,"year":88}

问题：如何在jsp页面中使用easy-ui 的datagrid将json格式的时间戳正常显示为："2016-06-06 12:00:00"？？？

jsp页面的easy-ui代码为：

 var columns = [ [  {
        field : 'pickdate',
        title : '取件日期',
        align : 'center',
        width : 100,
        formatter: function(value,row,index){
            return ？？？？这里改怎么写？？？;  
            }  
    }] ]; 

http://blog.csdn.net/idoiknow/article/details/8136093

         formatter: function(value,row,index){
            return Date(value.time).toLocaleString()
        }