程序代码:
servlet文件代码:
package com.blog;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/blogservlet")
public class blogservlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public blogservlet() {
super();}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
request.setCharacterEncoding("UTF-8");
String title = request.getParameter("title");
String content = request.getParameter("content");
String categoryId = request.getParameter("category");
System.out.println(title);
System.out.println(content);
System.out.println(categoryId);
}
}
web.xml我没有进行配置,因为在网上搜了下servlet 3.0好像不需要手动配置
一晚上都被这个问题卡住,求解决方法
附图n张
web.xml未改动如下
<?xml version="1.0" encoding="UTF-8"?>
blog
index.html
index.htm
index.jsp
default.html
default.htm
default.jsp
先确认你输入的地址是localhost:+端口号+:/blogservlet
打开web.xml
Myservlet
Myservlet
dd.Myservlet
Myservlet
/Myservlet
这个/Myservlet中间的内容就是servlet的路径
如果你是用tomcat的话,输入http://localhost:8080/blogservlet 应该可以,希望楼主把试过不行的url地址贴出来才好判断
TestServlet//类名
TestServlet//类名+包名
TestServlet//类名
/test//请求路径
看这个,servlet-mapping里的url-pattern才是真正的请求路径,即 /test
servlet>
servlet-name>TestServlet
servlet-class>TestServlet
/servlet>
servlet-mapping>
servlet-name>TestServlet
url-pattern>/test
/servlet-mapping>
肯定是xml的配置有问题(servlet的配置问题),找不到相应的servlert
一般情况下,都是在xml里面配置servlet,xml指定servlert的位置,在前台加载的时候,加载这个servlert
加载重启服务,应该就可以了