求帮助啊，线程同步问题， mutex为什么没有作用？

 #include<stdio.h>
#include<stdlib.h>
#include<windows.h>

int accnt1 = 0;
int accnt2 = 0;
double begin=0,end=0,time=0;
int i = 1;
HANDLE hMutex;

DWORD WINAPI run(LPVOID p){
    int counter = 0;
    int temp1,temp2,r;

    begin=GetTickCount();

    do{
        WaitForSingleObject(hMutex,INFINITE);
    //  printf("%d\n",GetCurrentThreadId());
        temp1 = accnt1;
        temp2 = accnt2;
        r = rand();
        accnt1 = temp1+r;
        accnt2 = temp2-r;
        ReleaseMutex(hMutex);

        counter++;
    }while(accnt1+accnt2==0&&counter<10000000);

    end =GetTickCount();
    time = end - begin;
    printf("Thread %d counter is %d \n time is %.4f \n",i,counter,time);
    i++;

    return 0;
}

int main(){
    hMutex = CreateMutex(NULL,FALSE,NULL);
    CreateThread(NULL,0,run,NULL,0,NULL);
    CreateThread(NULL,0,run,NULL,0,NULL);

    system("PAUSE");
    return 0;
}

加了锁为什么第一个线程还是无法完成啊

clude
#include
#include

int accnt1 = 0;
int accnt2 = 0;
double begin=0,end=0,time=0;
int i = 1;
HANDLE hMutex;

DWORD WINAPI run(LPVOID p){
int counter = 0;
int temp1,temp2,r;

begin=GetTickCount();

do{
    WaitForSingleObject(hMutex,INFINITE);
//  printf("%d\n",GetCurrentThreadId());
    temp1 = accnt1;
    temp2 = accnt2;
    r = rand();
    accnt1 = temp1+r;
    accnt2 = temp2-r;
    ReleaseMutex(hMutex);

    counter++;