#include
int main(void)
{
int years,days;
years=21;
days=years*365;
printf(" The years is %d. The days are %d.\n".years,days);
Return 0;
}
程序无法运行,提示错误。求大神解答。小弟在这里先谢谢啦。
printf(" The years is %d. The days are %d.\n",years,days);
把对应代码替换成这个就好了,printf输出格式的问题。
printf(" The years is %d. The days are %d.\n",years,days);
赋值的那两句等号要换成英文格式的,printf有个.要换成,
#include<stdio.h>
int main(void)
{
int years,days;
years=21;
days=years*365;
printf(" The years is %d. The days are %d.\n",years,days);
}
提问题错误的截图贴出来啊!
初学编程,一定要注意标点符号,全部用英文的。
还有return 0;