我的hibernate和spring 整合时getHibernateTemplate().find出现空指针问题

Spring组件: class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<!-- 数据库连接参数信息 -->

方言,映射描述都没问题,
/context:component-scan

<bean id="txManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
    <property name="sessionFactory" ref="sessionFactory"></property>
</bean>
<!-- 定义通知 -->
<tx:advice id="txAdvice" transaction-manager="txManager">
    <!-- 指定目标组件中的哪些方法采用哪种事务管理方式 -->
    <tx:attributes>
        <tx:method name="find*" read-only="true"  propagation="REQUIRED"/>
        <tx:method name="get*" read-only="true"     propagation="REQUIRED"/>
        <tx:method name="save*" propagation="REQUIRED"/>
        <tx:method name="update*" propagation="REQUIRED"/>
        <tx:method name="delete*" propagation="REQUIRED"/>
    </tx:attributes>
</tx:advice>
<!-- AOP配置，将通知和切入结合(目标对象) -->
<aop:config>
    <!-- 将所有DAO作目标 -->
    <aop:pointcut expression="within(org.dao..*)" 

<bean id="txManager" 
    class="org.springframework.orm.hibernate3.HibernateTransactionManager">
    <property name="sessionFactory" ref="sessionFactory">
    </property>
</bean>
<!-- 开启事务注解配置 -->
<tx:annotation-driven transaction-manager="txManager"/>

三张表:




UserInfo_SEQ

    <property name="grade" type="integer">
        <column name="GRADE"  />
    </property>
    <property name="Content" type="string">
        <column name="CONTENT"  />
    </property>
    <property name="createDate" type="date">
        <column name="CREATEDATE"  />
    </property>
    <property name="userId" type="integer"  update="false"
                      insert="false" >
        <column name="USERID"  />
    </property>
    <property name="flag" type="integer">
        <column name="FLAG"  />
    </property>
    <!-- 指定userInfo属性，采用many-to-one关系加载 -->
    <many-to-one name="userInfo" column="USERID"  lazy="false"
        class="org.entity.UserInfo">
    </many-to-one>
    <!-- 采用一(EventGrade)对多(Event)加载信息 -->
  <set name="event_Grades" >
        <key column="GRADE"></key>
        <one-to-many 
            class="org.entity.Event_Grade"/>
    </set>

table="EVENT_GRADE">



UserInfo_SEQ

</class>

UserInfo_SEQ

</class>

UserInfo_SEQ

    <property name="userName" type="string">
        <column name="USERNAME"  />
    </property>
     <!-- 采用一对多关系加载相关的Service记录 -->
  <set name="events" inverse="true" cascade="all">
        <!-- 指定关联条件字段，写外键字段 -->
        <key column="USERID"></key>
        <!-- 指定要采用的关系，要加载的数据类型 -->
        <one-to-many class="org.entity.Event"/>
  </set>
</class>

table="EVENT_GRADE">



UserInfo_SEQ

public Event findById(Integer id)throws DAOException{

// String findAllById = "from Event where id = ?";
// Object[] primes = {id};
List list = (List)this.getHibernateTemplate().find("from Event where id ="+id );
if(list!=null && !list.isEmpty()){
return list.get(0);
}
// Event event = (Event)this.getHibernateTemplate().get(Event.class,id);
// return event;
return null;

}

public List findGrade() throws DAOException {
String findGradeName = "select gradeName from Event_Grade ";
List names= new ArrayList();
System.out.println( this.getHibernateTemplate().find( findGradeName));
names.addAll( this.getHibernateTemplate().find(findGradeName));
if(!names.isEmpty()){
for (Object o : names) {
System.out.println(o);
}
return names;
}else {
System.out.println("DAOImpl为空");
return null;
}
}
测试返回的结果都为null,请哪位大神给解决一下,谢谢了

把错误信息贴出来塞。。。。。。