SELECT empfname, empsalary FROM qemp
WHERE empsalary <
(SELECT .90*AVG(empsalary) FROM qemp);
SELECT empfname, empsalary FROM qemp GROUP BY empsalary HAVING empsalary > 90*AVG(empsalary);
select empfname,empsalary from qemp
group by empsalary
having empsalary < .90*avg(empsalary)
不能groupby在empfname上
SELECT 1 AS flg, empfname,empsalary
FROM qemp
GROUP BY flg
HAVNG empsalary < .90*avg(empsalary)
上面我写的也不对 应该是不能用groupby