将while (scanf_s("%d%d%d", &n, &k, &m) == 3 && n)改成cin的形式怎么改
虽然我知道c++兼容c,但我想问一下用cin怎么表示上式
while(cin>>n>>k>>m && n)
//救济金发放
#include
#include
using namespace std;
const int maxn = 25;
int n, k, m;
int a[maxn];
int go(int p, int d, int t);//逆时针走t步,步长为d(-表示顺时针),返回新位置
int main()
{
while (cin >> n >> k >> m&&n)
{
for (int i = 1; i <= n; i++)
a[i] = i;
int leftn = n;
int p1 = n;
int p2 = 1;
while (left)
{
p1 = go(p1, 1, k);
p2 = go(p2, -1, m);
cout << setw(3) << p1;
leftn--;
if (p2 != p1)
{
cout << setw(3) << p2;
leftn--;
}
a[p1] = a[p2] = 0;
if (leftn)
cout << ",";
}
cout << endl;
}
return 0;
}
int go(int p, int d, int t)
{
while (t--)
{
do
{
p = (p + d + n - 1) % n + 1;
} while (a[p] == 0);
}
return p;
}
这是源码,我再vs上运行,你试一试
#include包含的是iostream和iomanip