如何用JS获取div下的子div

有多个独立的外层div,每个外层div内嵌一个内层的div,内层div在显示在外层div的下部。我要的效果是,当鼠标移入到一个外层div中时,改变这个外层div内的那个内层div。用Js怎么写代码?求大神指导

 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>无标题文档</title>
<script>
function MM_over(mmObj) {
    var mSubObj = mmObj.getElementsByTagName("div")[0];
    mSubObj.style.display = "block";
    mSubObj.style.backgroundColor = "#f60";
}
function MM_out(mmObj) {
    var mSubObj = mmObj.getElementsByTagName("div")[0];
    mSubObj.style.display = "none";

}
</script>

</head>

<body>
<div onmouseover="MM_over(this)" onmouseout="MM_out(this)" style="width:100px;position:relative;">sdfsdf
    <div style="width:100px;height:100px;display:none;position:absolute;left:0;top:15px;z-inde:5;"><p><a href="#">ssss</a></p><p><a href="#">ssss</a></p>
    </div>
</div>
</body>
</html>

给个id标识内层div或者用jq的children([expr]) 获取

var parentDiv = $("#a"); var childDiv = parentDiv.find("div");//如果只有一个这写没问题 var childDiv = parentDiv.find("div[id=a2]");//多个DIV