大神求帮助，，C#输出特殊符号

 在c#窗体中，怎么输出特殊，比如，{，}，&，%,@,$,就是0123456789上面的符号，
    代码如下，可是就是不出来

      private static string[] constant =   
  {   
    "0","1","2","3","4","5","6","7","8","9",  
    "a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z",   
    "A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z",
    "~","`","!","@","#","$","%","^","&","*","-","_","(",")","+","=","|","]","[","}","{",":",";","<",">","?","/"

  };
    public static string GenerateRandomNumber(int Length)
    {
        System.Text.StringBuilder newRandom = new System.Text.StringBuilder(100);
        Random rd = new Random();
        for (int i = 0; i < Length; i++)
        {
            newRandom.Append(constant[rd.Next(100)]);
        }
        return newRandom.ToString();
    }
}

 你写的太麻烦，这么写：
string static metachar = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!@#$%^&*()_+|-=\\{}[]:\";'<>?,./~`";
public static string GenerateRandomNumber(int Length)
{
    return string.Concat(metachar.OrderBy(x => Guid.NewGuid()).Take(Length));
}

你看看是不是你的数组定义除了问题，可以参照。http://www.cnblogs.com/zrlhappy/articles/614994.html

看一看转义字符。或者在每个特殊符号的字符串前面加@ 例如"\$"或者@"$"

你可以参考与之对应的ASCII值，然后反输出一下。参考看看http://wenku.baidu.com/view/54c98721af45b307e87197a7.html

看一看转义字符。或者在每个特殊符号的字符串前面加@ 例如"\$"或者@"$"