ssh中form向后台传值为null

jsp中form部分如下

用户名：
密码：
搜索:

下面这个表传回后台的值为空
Hibernate: select song0_.sid as sid3_, song0_.location as location3_, song0_.songname as songname3_ from Song song0_ where song0_.songname like '%null%'

这是查询语句
public List findByName(String songname) {
return us.find("from Song s where s.songname like '%" + songname + "%'");
}
想问问为什么form里的值传到后台变成null？

jsp和action中的获取必须对应起来，不然获取不到，要么修改jsp中的name要么修改action中获取

songName是否有set,get方法?
jsp 是否写name了？
你给的信息太少了

songname有get()和set()

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
@Entity
public class Song {
@Id
@GeneratedValue
private int sid;
private String songname;
private String location;

public int getId() {
    return sid;
}
public void setId(int id) {
    this.sid = sid;
}
public String getName() {
    return songname;
}
public void setName(String songname) {
    this.songname = songname;
}
public String getLocation() {
    return location;
}
public void setLocation(String location) {
    this.location = location;
}

}

jsp中有songname..粘没粘上去

用户名：
密码：

    <form action="search_search" method="post">
    <br/>搜索:<input name="songname" type="text">
    <br/><input type="submit" value="提交"/>
</form>

 <form action="search_search" method="post">
    <br/>搜索:<input name="songname" type="text">
    <br/><input type="submit" value="提交"/>
</form>
改一下,name属性和bean的set是一定要一致的，与私有变量名称不一定要一致。
<form action="search_search" method="post">
    <br/>搜索:<input name="name" type="text">
    <br/><input type="submit" value="提交"/>
</form>