PHP MySQL Update修改数据库失败,无警告报错

<?php

if(isset($_POST['submit'])&& $_POST['submit'])
    {
        $UID=$_GET['ID'];   
        $name=$_POST['uname'];
        $phone=$_POST['phone'];
        $email=$_POST['email'];
        $servername="localhost";
        $username = "root";
        $password = "";
        $dbname = "records";
        // 创建连接
        $conn = new mysqli($servername, $username, $password, $dbname);
        // 检测连接
        if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);}
        $sql="UPDATE user SET u_name=$name,u_phone=$phone,u_email=$email WHERE id='$UID'";
        if(mysqli_query($conn,$sql)){
            echo "修改成功！";}
        else{
            echo"修改失败！";}

        mysqli_close($conn);
        echo'<meta http-equiv="refresh" content="2;url=empManage.php">';
    }

?>

1.你所谓的失败是没有改掉你想要改的数据吧.先检查一下？UID的值对不对，未必是执行错误，可能是条件错误
2.在你的UPDATE里。$name,$phone,$email，前后都缺少单引号

无警告报错，错误信息是什么？

打印一下你那条sql，首先看是否有报错，接下来再注意那几个变量的地方

$sql="UPDATE user SET u_name=$name,u_phone=$phone,u_email=$email WHERE id='$UID'";

应该为

$sql="UPDATE user SET u_name=" + $name + ",u_phone=" + $phone" + ",u_email=" + $email + " WHERE id=" + $UID;

"UPDATE user SET u_name=$name,u_phone=$phone,u_email=$email WHERE id='$UID'"，这句SQL语句仔细查查。